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fredd [130]
2 years ago
15

Rutherford created a planetary model for atoms after his experiments. Imagine if Rutherford's idea that electrons radiate energy

while orbiting around a nucleus was true. Which other model or scientific idea would have been strengthened by this? Bohr's model of the atom would have been strengthened because Bohr proposed that the energy of electrons is continuous. Bohr's model of the atom would have been strengthened because Bohr proposed that electrons can have only certain energy values. The idea that atoms are unstable would have been strengthened because the orbiting electron would lose energy and fall into the nucleus. The idea that atoms are unstable would be strengthened because the orbiting electron would absorb energy while moving and escape the pull from the nucleus.
Chemistry
2 answers:
Lera25 [3.4K]2 years ago
6 0

Answer:

The idea that atoms are unstable would have been strengthened because the orbiting electron would lose energy and fall into the nucleus.

Explanation:

Based on classical mechanics an electron would spiral and fall on the nucleus thus collapsing the atom. But it was quantum mechanics that proposed that electrons move in definite orbits around the nucleus. Electrons absorb a definite quantum of energy and move from a lower state to an excited state. Also electrons release a definite quantum of energy and move from excited to more stable state.

Liono4ka [1.6K]2 years ago
5 0

The idea that atoms are unstable would have been strengthened because the orbiting electron would lose energy and fall into the nucleus.

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Bismuth(III) sulfate is an ionic compound formed from Bi3+ and SO42-. What is the correct way to represent the formula?
Hitman42 [59]

Answer:

Bi2(SO4)3

Explanation:

Bismuth(iii) sulfate is an ionic compound therefore, their is transfer of electron. Ionic compound has both cations and anions. The cations is positively charged ion while the anions is negatively charged ions. The cations loses electron to become positively charged while the anions gains electron to become negatively charged.

From the compound above, Bismuth(iii) sulfate the cations will be Bismuth ion which loses 3 electrons. The anions is the sulfate ion (S04)2- with a -2 charge.

The chemical formula can be computed from the charge configuration as follows

Bi3+  and (SO4)2-

cross multiply the charges living the sign behind to get the chemical formula

Bi2(SO4)3

Note the final chemical formula, the numbers are sub scripted

4 0
2 years ago
Please help!!
Sati [7]

In a chemical reaction, the limiting reagent is the chemical being used up while the excess reactant is the chemical left after the reaction process.

Before calculating the limiting and excess reactant, it is important to balance the equation first by stoichiometry.

C25N3H30Cl + NaOH = C25N3H30OH + NaCl

Since the reaction is already balanced, we can now identify which is the limiting and excess reagent.

First, we need to determine the number of moles of each chemical in the equation. This is crucial for determining the limiting and excess reagent.

<span>Assuming that there is the same amount  of solution X for each reactant</span>

1.0 M NaOH ( X ) = 1.0 moles NaOH

1.00 x 10-5 M C25N3H30Cl ( X ) = 1.00 x 10-5 moles C25N3H30Cl

<span>The result showed that the crystal violet has lesser amount than NaOH. Thus, the limiting reactant in this chemical reaction is crystal violet and the excess reactant is NaOH.</span>

3 0
2 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
2 years ago
Summarize the process a scientist goes through to come up with a<br> satisfactory solution.
maria [59]
Guess and check, test, trial and error, completion.
6 0
2 years ago
Convert 4.77x10^24 molecules of SO2 to grams
tensa zangetsu [6.8K]
Those are the correct steps, young chemist. Don't be discouraged by an insane answer. 
5 0
2 years ago
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