Velocity with wind = 1,980 / 4.5 = 440 mph
Velocity against wind =1,980 / 5.5 = 360 mph
Plane in still air - wind speed = 360
Plane in still air + wind speed =440
Adding both equations:
2*Plane in still air = 800
Plane in still air = 400 mph
Plane in still air + wind speed =440
Therefore, wind speed = 40 mph
Bryan spends T=15x
320 divided by 15 is and average of $21 per week
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
11, 12, 15, 16, 20, 20, 25
Mean: 17
The range is 25-11 = 14 (the numbers in bold)
The interquartile range is 20-12=8 (the numbers underlined)
The mean absolute deviation is: 4; this is found by finding how far each number is from 17 (mean): 6,5,2,1,3,3,8 (28) and dividing by 7.
Part B:
The prices vary by no more that $14 (range).
<span>The middle half of the prices vary by no more than $8 (IQR).
</span>
<span>The admission prices differ from the mean price by an average of $4 (MAD).</span>
