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3241004551 [841]
2 years ago
8

A school spent $150 on advertising for a breakfast fundraiser. Each plate of food was sold for $8.00 but cost the school $2.00 t

o prepare. After all expenses were paid, the school raised $2,400 at the fundraiser. Which equation can be used to find x, the number of plates that were sold?
Mathematics
1 answer:
KATRIN_1 [288]2 years ago
7 0
8.00 divided by 2400 Is 300...
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Nick is 30 years less than 3 times Rays age. If the sum of their ages is 74,how old are each of the men? Solve and write an equa
zaharov [31]
Nick = n
Ray = r

n=3r-30
n+r=74

3r-30+r=74
4r-30=74
4r=104
r=26
n=26*3-30
n=78-30
n=48
Nick is 48 years old and Ray is 26 years old
Hope this helps.
5 0
2 years ago
LeAnn is purchasing giftwrap for a box that measures 8 inches long, 6 inches wide, and 6 inches tall. Calculate the total area o
Pavel [41]

Let

L---------> the length side of the box

W--------> the width side of the box

H-------> the height of the box

we know that

L=8\ in\\W=6\ in\\H=6\ in

the surface area of the box is equal to

S=2*area\ of\ the\ base+perimeter\ of\ the\ base*H

<u>Find the area of the base</u>

A=L*W=8*6=48\ in^{2}

<u>Find the perimeter of the base</u>

P=2*L+2*W=2*8+2*6=28\ in

<u>Find the surface area</u>

S=2*48+28*6

S=264\ in^{2}

therefore

<u>the answer is</u>

the total area of the box that will be covered in gift wrap is 264\ in^{2}

8 0
2 years ago
Read 2 more answers
Jacob spends 60 minutes in the gym every day doing freehand exercises and running on the treadmill. He runs on the treadmill 30
elixir [45]

Answer:

a.

x + y = 60

x = y + 30

b.

substitution:

(y + 30) = y = 60

2y + 30 = 60

2y = 30

y = 15

15 minutes for freehand

c.

No, because if he spends 40 minutes on the treadmill, he would have spent 10 minutes for freehand exercises. His total time in the gym would be 50 minutes, not 60.

8 0
2 years ago
You plan to rent a car from XYZ Car Rental Company for a flat rate of $35 a
vagabundo [1.1K]

Answer:

The piece-wise function is;

f\left (x  \right ) = \begin{cases} \$ 45 \times  x & \text{ if } x \leq 3  \ days \\ \$40 \times x & \text{ if } x > 3 \ days\end{cases}

Step-by-step explanation:

The flat rate for renting the car = $35 per day

The amount charged as insurance fee per day for renting the car for 3 days or less = $10

The insurance fee charged per day when the car is rented for more than 3 days = $5

Let the number of days = x

Therefore, we have;

For x ≤ 3, f(x) = 35 × x + 10 × x = x × (35+10) = 45·x

For x > 3, f(x) = 35 × x + 5 × x = x × (35+5) = 40·x

Therefore;

The charge rate for renting the car for less than or equal to 3 days = 45·x

The charge rate for renting the car for more than 3 days = 40·x

The piece-wise function can be presented as follows;

f\left (x  \right ) = \begin{cases} \$ 45 \times  x & \text{ if } x \leq 3  \ days \\ \$40 \times x & \text{ if } x > 3 \ days\end{cases}

3 0
2 years ago
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
2 years ago
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