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Eddi Din [679]
2 years ago
15

Assume that a population of newly discovered small creatures called “porgs” in a remote island lays eggs with three distinct app

earances: patterned with dots, white, or dark grey. Last year, the porgs laid 30 dotted eggs, 40 grey eggs, and 15 white eggs. You randomly selected 25 eggs, 10 of which were dotted, 13 were grey and 2 were white. Based on this information, what is the probability that you would only collect 2 white eggs?
Mathematics
2 answers:
vovangra [49]2 years ago
5 0

Answer:

0.029

Step-by-step explanation:

Last year, the porgs laid 30 dotted eggs, 40 grey eggs, and 15 white eggs.

Total eggs = 30+40+15 = 85 eggs

White eggs = 15

So, probability of getting 1 white egg = \frac{\text{No. of white eggs}}{\text{Total no. of eggs}}

                                                              = \frac{15}{85}

Remaining white eggs = 14

Total eggs remaining = 84

Probability of getting 1 white egg on second draw   = \frac{14}{84}

So, the probability that you would only collect 2 white eggs =\frac{15}{85} \times \frac{14}{84}

                                                                                                   =0.029

Hence the probability that you would only collect 2 white eggs is 0.029.

Slav-nsk [51]2 years ago
4 0

you have a 1/12.5 chance of getting a white egg. so the theoretical possibility of getting only two white eggs is 1/156.25. so it is very unlikely to get two white eggs

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