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GenaCL600 [577]
2 years ago
5

A restaurant owner needs to order at least 176 filet mignon steaks to be stocked for a busy Friday night. He only has room to st

ore 321 steaks in his refrigerator. Model the number of steaks the restaurant owner can order, using a compound inequality.
x ≥ 176 and x ≤ 321
x ≤ 176 and x ≥ 321
x ≤ 176 and x ≤ 321
x ≥ 176 and x ≥ 321
Mathematics
1 answer:
Nikolay [14]2 years ago
5 0

Answer:

x ≥ 176 and x ≤ 321

Step-by-step explanation:

Let

x -----> the number of steaks the restaurant owner can order

we know that

x\geq 176 ----> inequality A

x\leq 321 ----> inequality B

so

the compounded inequality is equal to

176 \leq x \leq 321

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Drag the values to order them from least to greatest, with the least at the top. Item 2 moved to position 3. 79 − − √ + 63 − − √
Nonamiya [84]

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi

By using calculator, let's convert those numbers into decimal form:

\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56

So arranging from least to greatest we have:

\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

Put another way:

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

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Leni [432]
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The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3. Suppose 36 golfers play
kondaur [170]

Answer:

the probability that the exceeded 65 = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

Step-by-step explanation:

<u>Step 1</u>:-

The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.

mean (μ) = 64

standard deviation (σ) =3

by using normal distribution

given (μ) = 64 and  (σ) =3

i) when x =65

z = \frac{x-mean}{S.D} = \frac{65-64}{3} = 0.33 >0

P( X≥ 65) = P(z≥0.33)

              = 0.5 - A(z₁)

              = 0.5 - 0.1293 (see normal table)

             = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

                                               

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2 years ago
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Answer:

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Step-by-step explanation:

We have been given that Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. We are asked to find the amount of candy bought by Mr. Snow in kilograms.

First of all, we will find the amount of candy in grams by multiplying 90 grams by 14 as:

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We know that 1 kilogram is equal to 1000 grams. To convert 1260 grams into kg, we will divide 1260 by 1000 as:

\text{Amount of candy bought in kilograms}=\frac{1260}{1000}

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