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2 years ago

A fish has armored plates that enable it to handle the extreme pressure in the deepest, darkest aquatic ecosystem.

Chemistry

2 answers:

love history [14]2 years ago

6 0

Answer:

the open ocean

Explanation:

just took the test

Nastasia [14]2 years ago

6 0

Answer:

the open ocean

Explanation:

i just took the test on edge

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The number of organisms that the environment in an ecosystem can handle is called its _____.

Basile [38]

The answer to this question is "carrying capacity." The term "growth rate," refers to how fast a population grows, and the term "population density," refers to the number of organisms located within a specific area. Carrying capacity is correct because is directly addresses the maximum number of organisms that an ecosystem can handle, as opposed to how fast they are growing or how many there currently are.

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2 years ago

Read 2 more answers

A gaseous compound is 30.4% nitrogen and 69.6% oxygen. a 6.06-gram sample of gas occupies a volume of 1.00 liter and exerts a pr

aksik [14]

A gaseous compound is 30.4% nitrogen and 69.6% oxygen by mass. A 5.25-g sample of the gas occupies a volume of 1.00 L and exerts a pressure of 1.26 atm at -4.0°C. Which of the following is its molecular formula?

1) NO2

2) N3O6

3) N2O5

4) N2O4

5) NO

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2 years ago

Lars observes a substance to be a solid and to float in water at room temperature (23°C). Based on the given properties, which s

Triss [41]

Answer:

D. Sulfur Hexafluride

Explanation:

above it says the substance floats above water at room temperature and lists some substances and their density at room temp!
we know that the density of water is 1.0 so the substance in order for it to float has to be less than 1.0 and the densities for Sulfer Hexa, are all less than 1!!

I hope this helped !!

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2 years ago

3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.

kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

$Percent by mass=\frac{mass of solute}{mass of solution} *100$

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

mass of solute: 3.55 g
mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

$Percentbymass=\frac{3.55}{91.55}*100$

Percent by mass= 3.88%

<u><em>The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%</em></u>

5 0

2 years ago

The first step in the Ostwald process for producing nitric acid is 4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g). If the reaction of 1

aniked [119]

Answer: The percentage yield of the given reaction is 77.33%.

Explanation:

Moles is calculated by using the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of Ammonia:

Given mass of ammonia = 150g

Molar mass of ammonia = 17 g/mol

Putting values in above equation, we get:

$\text{Moles of ammonia}=\frac{150g}{17g/mol}=8.82moles$

Moles of Oxygen

Given mass of oxygen = 150g

Molar mass of oxygen = 32 g/mol

Putting values in above equation, we get:

$\text{Moles of oxygen}=\frac{150g}{32g/mol}=4.6875moles$

For the given chemical equation:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

By Stoichiometry,

5 moles of oxygen reacts with 4 moles of ammonia.

So, 4.6875 moles of oxygen will react with = $\frac{4}{5}\times 4.6875=3.75moles$ of ammonia

As, moles of ammonia required is less than the calculated moles. Hence, ammonia is present in excess and is termed as excess reagent.

Therefore, oxygen is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the given reaction:

5 moles of oxygen gas produces 4 moles of nitric oxide

So, 4.6875 moles of oxygen gas will produce = $\frac{4}{5}\times 4.6875=3.75moles$ of nitric oxide

Now, to calculate the theoretical amount of nitric oxide, we use equation 1:

Molar mass of nitric oxide = 30 g/mol

$3.75mol=\frac{\text{Given mass}}{30g/mol}$

Given mass of nitric oxide = 112.5 g

Now, to calculate the percentage yield, we use the formula:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield = 87 g

Theoretical yield = 112.5 g

Putting values in above equation, we get:

$\%\text{ yield}=\frac{87}{112.5}\times 100=77.33\%$

Hence, the percentage yield of the given reaction is 77.33%.

5 0

2 years ago