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OverLord2011 [107]
2 years ago
14

Find the product of (4x + 3y)(4x − 3y).

Mathematics
2 answers:
EastWind [94]2 years ago
5 0

Answer:

It's B

Step-by-step explanation:

B,     16x2-9y2

USPshnik [31]2 years ago
3 0

Answer:  The correct option is (B) 16x^2-9y^2.

Step-by-step explanation:  We are given to find the following product :

P=(4x+3y)(4x-3y)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To find the given product, we will be using the following formula :

(a+b)(a-b)=a^2-b^2.

The product (i) can be calculated as follows :

P\\\\=(4x+3y)(4x-3y)\\\\=(4x)^2-(3y)^2\\\\=16x^2-9y^2.

Thus, the required product is 16x^2-9y^2.

Option (B) is CORRECT.

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A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening
Gala2k [10]
Since the parabola passes by the center its equation is:

y = ax². But it opens downward, that means the coefficient a is negative.

Then the equation becomes:

y = - ax², with x = 0 as its axis of symmetry.

We are given that the height is 84 ft when the opening downward is 42 ft.
That means to the (height) y, corresponds x =+21 & x=-21 (due to symmetry).
In order to calculate a let's plug y & x with their related values:

y = - ax²

84 = - a(21)²

84 = - a(441) and a = - 84/441 ↔ a = - 4/21

 And the final equation is : y = -4/21. x²
3 0
2 years ago
Suppose we have a group of 10 light users and 10 heavy users. what is the probability that exactly 3 of the 20 users are hiv pos
dmitriy555 [2]

Answer: The answer is 30%.


Step-by-step explanation:  Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.

We have the following four possible cases -

(i) All 3 are light users.

(ii) 1 is a light user and 2 are heavy users.

(iii) 2 are light users and 1 is a heavy user.

(iv) All 3 are heavy user.

Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

p\\\\=\dfrac{3\times 0.45+1\times 0.45+2\times 0.55+2\times 0.45+1\times 0.55+3\times 0.55}{20}\\\\=\dfrac{6}{20}\\\\=0.3\\\\=30\%.

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4 0
2 years ago
A thumbtack that is tossed can land point up or point down. The probability of a tack landing point up is 0.2. A simulation was
sweet-ann [11.9K]

Answer:

Option C: 0.28

Step-by-step explanation:

This is a binomial probability distribution problem.

Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;

P(X ≥ 2) = P(2) + P(3) + P(4) + P(5)

From the histogram;

P(5) = 0.02

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Thus;

P(X ≥ 2) = 0.19 + 0.05 + 0.02 + 0.02

P(X ≥ 2) = 0.28

8 0
2 years ago
Read 2 more answers
Find cot 0 if cos 0=3/13
natta225 [31]
3/4 root 10
you make a right triangle. use Pythagorean theorem. and find the opposite side. then reduce the radical of 160. and do tan and then flip them around to make cot.
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Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

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The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

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after the 3rd day,

B =( B_0 *3*3)*3

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Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

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Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

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