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dedylja [7]
1 year ago
6

Use Green's Theorem to evaluate F · dr. C (Check the orientation of the curve before applying the theorem.) F(x, y) = e−x + y2,

e−y + x2 , C consists of the arc of the curve y = cos(x) from − π 2 , 0 to π 2 , 0 and the line segment from π 2 , 0 to − π 2 , 0
Mathematics
1 answer:
Yuki888 [10]1 year ago
3 0

Notice that C is traversed clockwise. Green's theorem applies to curves with a counterclockwise orientation, so we'll have to multiply the area integral by -1.

By Green's theorem, with the vector field \vec F(x,y)=P(x,y)\,\vec\imath+Q(x,y)\,\vec\jmath,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=-\iint_D\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\right)\,\mathrm dA

where D is the region with boundary C. The partial derivatives are

\dfrac{\partial(e^{-y}+x^2)}{\partial x}=2x

\dfrac{\partial(e^{-x}+y^2)}{\partial y}=2y

so that the double integral is

\displaystyle\iint_D\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\right)\,\mathrm dA=\int_{-\pi/2}^{\pi/2}\int_0^{\cos x}2(y-x)\,\mathrm dy\,\mathrm dx=\boxed{\frac\pi2}

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Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim. The foundation chair for a hosp
slavikrds [6]

Answer:

For this case we want to test if the mean number of filled overnight beds is over​ 523. If X represent our random variable "number of filled overnight beds", the system of hypothesis are:

Null Hypothesis: \mu \leq 523

Alternative hypothesis: \mu > 523

And for this case after conduct the test is FAIL to reject the null hypothesis. So then we can conclude that the claim that the number of filled overnight beds is over​ 523 is not statistically supported

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

For this case we want to test if the mean number of filled overnight beds is over​ 523. If X represent our random variable "number of filled overnight beds", the system of hypothesis are:

Null Hypothesis: \mu \leq 523

Alternative hypothesis: \mu > 523

And for this case after conduct the test is FAIL to reject the null hypothesis. So then we can conclude that the claim that the number of filled overnight beds is over​ 523 is not statistically supported

6 0
1 year ago
In equilateral ∆ABC with side a, the perpendicular to side AB at point B intersects extension of median AM in point P. What is t
Sergeeva-Olga [200]

Answer:

Perimeter  = (2 + √3)·a

Step-by-step explanation:

Given: ΔABC is equilateral and AB = a

The diagram is given below :

AM is a median , PB ⊥ AB , PM = b

Now, by using properties of equilateral triangle, median is perpendicular bisector and each angle is of 60°.

We get, ∠AMB = 90°. So, by linear pair ∠AMB + ∠PMB = 180° ⇒ ∠PMB = 90°. Also, ∠ABC = 60° and ∠ABP = 90° (given) So, ∠PBM = 30°

Since, AM is perpendicular bisector of BC. So,

MB = \frac{a}{2}

Now in ΔAMB , By using Pythagoras theorem

AB^{2}=AM^{2}+MB^{2}\\AM^{2}=AB^{2}-MB^{2}\\AM^{2}=a^{2}-(\frac{a}{2})^{2}\\AM=\frac{\sqrt{3}\cdot a}{2}

Now, in ΔBMP :

sin\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\sin\thinspace 30^{o}=\frac{\text{MB}}{\text{PB}}\\\\PB=\frac{\text{MB}}{\text{sin 30}}\\\\PB=\frac{\frac{a}{2}}{\frac{1}{2}}\implies PB = a\\\\tan\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Base}}\\\\tan\thinspace 30^{o}=\frac{\text{MB}}{\text{PM}}\\\\PM=\frac{\text{MB}}{\text{tan 30}}\\\\PM=\frac{\frac{a}{2}}{\frac{1}{\sqrt3}}\implies PM=b= \frac{\sqrt{3}\cdot a}{2}

Perimeter of ABM = AB + PB + PM + AM

\text{Perimeter = }a+a+b+ \frac{\sqrt{3}\cdot a}{2}\\\\=2\cdot a + \frac{\sqrt{3}\cdot a}{2} +\frac{\sqrt{3}\cdot a}{2}\\\\=2\cdot a +\sqrt{3}\cdot a\\\\=(2+\sqrt3})\cdot a

Hence, Perimeter of ΔABP = (2 + √3)·a units

3 0
1 year ago
The cylindrical part of a architectural column has a height of 325 cm and a diameter of 30 cm. Find the volume of the cylindrica
lyudmila [28]

Answer:

V=229612.5\ cm^3

Step-by-step explanation:

Given that,

The height of a cylinder, h = 325 cm

Diameter, d = 30 cm

Radius, r = 15 cm

We need to find the volume of the cylinder. The formula for the volume of a cylinder is given by :

V=\pi r^2h

Putting all the values,

V=3.14\times (15)^2\times 325\\\\V=229612.5\ cm^3

So, the volume of the cylinder is 229612.5\ cm^3.

4 0
1 year ago
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bixtya [17]
First solve the slope, mm = ( y1 - y2 ) / ( x1 - x2 )m = ( 3555 - 3240 ) / ( 1 - 8 ) m = - 45 gal / day
then solve the y intercept, by = mx + b
3555 = (-45)(1) + b3555 = -45 + bb = 3555 + 45b = 3600
so day 50
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5 0
1 year ago
-3x+10y=-20 <br> -8x+2y=11 elimination method
Semenov [28]
(-75/37, -193/74) is your answer .-.
5 0
2 years ago
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