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1 year ago

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The cylindrical part of a architectural column has a height of 325 cm and a diameter of 30 cm. Find the volume of the cylindrica

l part of the column. Use 3.14 for π and round your answer to the nearest cubic centimeter if needed.

2 answers:

lyudmila [28]1 year ago

4 0

Answer:

$V=229612.5\ cm^3$

Step-by-step explanation:

Given that,

The height of a cylinder, h = 325 cm

Diameter, d = 30 cm

Radius, r = 15 cm

We need to find the volume of the cylinder. The formula for the volume of a cylinder is given by :

$V=\pi r^2h$

Putting all the values,

$V=3.14\times (15)^2\times 325\\\\V=229612.5\ cm^3$

So, the volume of the cylinder is $229612.5\ cm^3$ .

My name is Ann [436]1 year ago

3 0

Answer:

229612.5

229613

Step-by-step explanation:

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Elias likes to read during his summer breaks. The table below shows the number of pages in each book he read last summer and the

user100 [1]

Answer:

A.The modes differ by 40 and the ranges differ by 40.

Step-by-step explanation:

The mode of a data set is the value that occurs most often.

For the data from last summer, the value 190 is in the list twice, while all other values are only in once. This means 190 is the mode.

For the data from this summer, the value 150 is in the list twice, while all other values are only in once. This means 150 is the mode. This also means the difference in modes is 190-150 = 40.

The range is the difference between the maximum and minimum values in a data set. For last summer's data, the maximum is 220 and the minimum is 140; this gives us 220-140 = 80 for the range.

For this summer's data, the maximum is 190 and the minimum is 150; this gives us 190-150 = 40 for the range. This means the difference in ranges is 80-40 = 40.

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1 year ago

Read 2 more answers

Each of 16 students measured the circumference of a tennis ball by four different methods, which were:Method A: Estimate the cir

lys-0071 [83]

Answer:

a) $\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

b) $Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

c) $\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

Step-by-step explanation:

Data given

Assuming the following data:

Method A: 18.0, 18.0, 18.0, 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0,25.0,26.0,26.4

Method B: 18.8, 18.9, 18.9, 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0, 22.0,22.0,23.6

Method C: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5,21.5,21.5,21.6

Method D: 20.0, 20.0, 20.0,-20.0, 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5, 21.6, 22.1,22.3.

Part a

The sample mean is defined as:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

If we apply this formula for the four methods we got:

$\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

Part b

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

$Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

Part c

The trimmed mean by 20% means that we need to calculate removing the 20% from each of the tails, the 20% of 16 is 3.2, so we need to remove 3 observations from both ends of the data like this:

Method A: 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0

Method B: 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0

Method C: 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5

Method D: 20.0 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5.

If we calculate the mean for each method we got:

$\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

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1 year ago

Derrick needs to figure out how he’s doing on his test scores so far this year. You can help by calculating the mean and the med

romanna [79]

Answer:

74.4 ,81.5 , median

Step-by-step explanation:

ed20 answers

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1 year ago

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Find the indicated values: <br> Given: OA=AC=2<br> AB is a tangent line<br> Find: AB

nlexa [21]

Step-by-step explanation:

OA=AC=OC=2 (equal triangle)

which means angle O =60 degree

tan 60 = AB / 2

AB = 2 tan 60 =

$2 \sqrt{3}$

3 0

1 year ago

A simple random sample of 100 concert tickets was drawn from a normal population. The mean and standard deviation of the sample

alexandr402 [8]

Answer:

We accept the null hypothesis and the population mean is $120.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Sample mean, $\bar{x}$ = $120

Alpha, α = 0.01

Sample standard deviation, s = $25

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 125\\H_A: \mu \neq 125$

We use two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = -2.0$

p-value one tail= 0.024

p-value two tail= 0.048

Conclusion:

Since the p-value for two tailed test is greater than the significance level, we fail to reject the null hypothesis and accept it.

Thus, the population mean is $120.

6 0

1 year ago