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Airida [17]
2 years ago
7

Kelly bought a new car for $20,000. The car depreciates at a rate of 10% per year. Write an equation to model the car’s value. U

se your equation to determine the value of the car six years after Kelly purchased it
Mathematics
1 answer:
Citrus2011 [14]2 years ago
5 0

Answer:

P=P'(1-R/100)^T

Where P = Final price

P'=Initial price

T=Time

R=Rate of Depreciation.

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Suppose X is the breaking strength (newtons) of a material, and X is normally distributed with
Veronika [31]

Answer:

a) 0.997 is the  probability that the breaking strength is at least 772 newtons.

b) 0.974  is the probability that this material has a breaking strength of at least 772 but not more  than 820    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 800 newtons

Standard Deviation, σ = 10 newtons

We are given that the distribution of  breaking strength is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( breaking strength of at least 772 newtons)

P(x \geq 772)

P( x \geq 772) = P( z \geq \displaystyle\frac{772 - 800}{10}) = P(z \geq -2.8)

= 1 - P(z

Calculation the value from standard normal z table, we have,  

P(x \geq 772) = 1 - 0.003 = 0.997 = 99.7\%

0.997 is the  probability that the breaking strength is at least 772 newtons.

b) P( breaking strength of at least 772 but not more  than 820)

P(772 \leq x \leq 820) = P(\displaystyle\frac{772 - 800}{10} \leq z \leq \displaystyle\frac{820-800}{10}) = P(-2.8 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2.8)\\= 0.977 - 0.003 = 0.974 = 97.4\%

P(772 \leq x \leq 820) = 97.4\\%

0.974  is the probability that this material has a breaking strength of at least 772 but not more  than 820.

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Answer:

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Step-by-step explanation:

The additive inverse of a term is formed by changing the sign. The additive inverse of the polynomial is formed by changing the sign of every term.

If we call the expressions on the left (top-to-bottom) 1, 2, 3, 4, and those on the right A, B, C, D, then the match-up <em>in this presentation of the question</em> is ...

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