Answer: 1 5/12 cups of flour leftover
Step-by-step explanation: First, add 4 2/3 + 5 1/4. This gives you 9 11/12. 9 11/12 - 8 1/2 = 1 5/12.
The given complex number is
z = 1 + cos(2θ) + i sin(2θ), for -1/2π < θ < 1/2π
Part (i)
Let V = the modulus of z.
Then
V² = [1 + cos(2θ)]² + sin²(2θ)
= 1 + 2 cos(2θ) + cos²2θ + sin²2θ
Because sin²x + cos²x = 1, therefore
V² = 2(1 + cos2θ)
Because cos(2x) = 2 cos²x - 1, therefore
V² = 2(1 + 2cos²θ - 1) = 4 cos²θ
Because -1/2π < θ < 1/2π,
V = 2 cosθ PROVEN
Part ii.
1/z = 1/[1 + cos2θ + i sin 2θ]

The denominator is

Therefore

The real part of 1/ = 1/ (constant).
Answer: B. Blind experiment
Step-by-step explanation: While conducting an experiment, experimenters may aim to eliminate factors which are very likely to cause bias and hence affect the veracity of the study. In the scenario above, the participants of the study (coworkers) were only provided with samples of the two coffee types without any of them knowing if it was the coffee they drank now or the new coffee brand. Hence, withholding such information from the participant is a technique in experimenting called blinding. Because, the information could affect the outcome and hence objective of the study as the participants were already partial towards the present coffee being consumed.
Answer: 1.8 bags
Step-by-step explanation:
From the question, given that robby have 4 4/9 bags of pet food, 2/5 were dog food
2/5 of 4 4/9 = dog foods
Convert 4 4/9 to proper fraction= 40/9
2/5 of 40/9 means 2/5 × 40/9
= 16/9
= 1.78 or 1.8
I hope this helps, please mark as brainliest answer.
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Answer with explanation:</h2>
To write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3
Let n be the number, then -3 < n ≤3 .
On number line we mark open circle at -3 (since it has a strictly less than sign) and a closed circle at 3 (since it has a less than and equal to sign) .
To the required inequality that shows all the numbers greater than (−3) but less than or equal to 3 : -3 < n ≤3 and the number line is represented below.