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polet [3.4K]
2 years ago
4

Sheila is looking at some information for the obstacle course she is interested in completing. The x-coordinate is the number of

the obstacle, while the y-coordinate is the average time to complete the obstacle, measured in minutes.
(1, 8.25), (2, 9.075), (3, 9.9825), (4, 10.98075)

Help Sheila use an explicit formula to find the average time she will need for the 8th obstacle.

f(8) = 8.25(1.1)^8; f(8) = 17.685
f(8) = 8.25(1.1)^7; f(8) = 16.077
f(8) = 1.1(8.25)^7; f(8) = 2861345
f(8) = 1.1(8.25)^8; f(8) = 23606102
Mathematics
2 answers:
Setler79 [48]2 years ago
7 0

Answer:

B // f(8) = 8.25(1.1)^7; f(8) = 16.077

Step-by-step explanation:

I'm Pretty Sure She's Got It ^^^

Sedbober [7]2 years ago
5 0

Answer:

f(8) = 8.25(1.1)^7; f(8) = 16.077

Step-by-step explanation:

In order to calculate the explicit formula we need to look at the y coordinates. All the options list the formula of a Geometric Sequence, so we will find which sequence defines the given coordinates:

The sequence is:

8.25, 9.075, 9.9825, 10.98075

f(1) = First term of the Sequence = 8.25

r = Common Ratio = Ratio of two consecutive terms = \frac{9.075}{8.25} = 1.1

The explicit formula for a geometric sequence is:

f(n)=f(1)(r)^{n-1}

Using the values, we get:

f(n)=8.25(1.1)^{n-1}

For 8th term, we have to replace n by 8:

f(8)=8.25(1.1)^{8-1}\\\\ f(8)=8.25(1.1)^{7} \\\\ f(8)=16.077

So, second option gives the correct answer: f(8) = 8.25(1.1)^7; f(8) = 16.077

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Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat
Ksenya-84 [330]

Answer:

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

5 0
1 year ago
A few people who have a particular disease take part in a medical trial that tests the effect of a medicine on the disease. Half
Rom4ik [11]

Answer:

1.The probability that a person gets well is 70%,

2.the probability that the person was cured because of the medicine is 60%

Step-by-step explanation:

chance of curing by medicine=60%

chance of curing without medicine=10%

total chance of curing=60%+10%=70%

chance of person being cured by medicine=60%

3 0
2 years ago
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $
nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within 1\frac{1}2 mi, charges = $1.25

For delivery within 1\frac{1}2 mi - 1\frac{3}4 mi, charges = $1.70

For delivery within 1\frac{3}4 mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2\frac{1}4 mi, charges = $2.60

For delivery within 2\frac{1}4 mi - 2\frac{1}2 mi, charges = $3.05

For delivery within 2\frac{1}2 mi - 2\frac{3}4 mi, charges = $3.50

For delivery within 2\frac{3}4 mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3\frac{1}4 mi, charges = $4.40

So, every 0.25 mi or \frac{1}4 mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of 3\frac{1}8 miles lies within the range 3 mi - 3\frac{1}4 mi.

So actual charges after increase of 10%

\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}

6 0
2 years ago
Alexa owns a total of 45 fiction and nonfiction books. If the number of fiction books is 15 more than 4 times the number of nonf
Vikentia [17]
What are the choices?
4 0
2 years ago
Nyoko needs to be at school at 7:45 AM. It takes her 15 minutes to walk to school, 5/12 hour to eat breakfast, 0.7 hour to get d
defon
So, she wants to be at school at 7.40 (5 mins early)

she needs:

15 mins
5/12 hours (which is \frac{5}{12} = \frac{25}{60}, so 25 mins

so far: 40 mins

then 0.7 and 0.15: we can add those, since they're in decimals: 0.85.

how many minutes is this?

\frac{85}{100} *60=  \frac{85}{10} *6=\frac{85}{5} *3=\frac{13}{1} *3=39

so 39 mins.

together with the previous 40, it's 79 minutes, which is 1 hour and 19 minutes: so she needs to wake up 1 hour and 19 minutes before 7.40 , which is

6.21!
6 0
2 years ago
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