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oee [108]
2 years ago
5

Mr. Markowski drives to his office one morning. After he leaves his house, he drives

Mathematics
1 answer:
ella [17]2 years ago
7 0
OMG I LOVE THE OFFICE, team dwight
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A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x)=-2x^2+20x+48h(x)=
Ad libitum [116K]

the maximum height is the y-value of the vertex.

h(x) = -2x² + 20x + 48

      <em>  a=-2, b=20, c=48</em>

x = \frac{-b}{2a} = \frac{-20}{2(-2)} = \frac{-20}{-4} = 5

h(5) = -2(5)² + 20(5) + 48

      =  -50   +  100   + 48

      =          50         + 48

      =                98

Answer: 98 meters

8 0
2 years ago
Triangle KLM represents a section of a park set aside for picnic tables. The picnic area will take up approximately 400 square y
svetoff [14.1K]
Given triangle KLM with two sides given as 45 yd and 20 yd and a 25 degree angle opposite the 20 yd side.

We find the angle made at the opposite of the 45 yd side using the sine rule as follows.
\frac{\sin{A}}{a} =  \frac{\sin{B}}{b}  \\  \frac{\sin{25^o}}{20} = \frac{\sin{B}}{45}  \\ \sin{B}= \frac{45\sin{25^o}}{20} = \frac{19.0178}{20} =0.9509 \\ B=\arcsin{(0.9509)}=71.97^o

Thus, the third angle is given by 180 - 25 - 71.97 = 83.03 degrees.

We also use the sine rule to find the third side of the triangle as follows.
\frac{\sin{A}}{a} = \frac{\sin{C}}{c} \\ \frac{\sin{25^o}}{20} = \frac{\sin{83.03^o}}{c} \\ c= \frac{20\sin{83.03^o}}{\sin{25^o}} = \frac{19.8522}{\sin{25^o}} =46.97 yds

Therefore, amount of fencing needed to surround the perimeter of the picnic area = 45 + 20 + 46.97 = 111.97 ≈ 120 yds
6 0
2 years ago
Read 2 more answers
For all real numbers a and b, 2a • b = a2 + b2 Is this true or false? Explain why it false or true.
Andru [333]

Answer:

It's false.... correct is a2+2ab+b2

Step-by-step explanation:

This cannot be factored anymore although. when we try to substitute a with 5 and b with 2, the answer in the right hand side of the equation is -9.

That's why it's false.

3 0
2 years ago
Find the height of a clock tower if the angle of elevation from a horizontal point 430 m from its base is 40°.
zaharov [31]

\\ \sf\longmapsto tan40=\dfrac{P}{430}

\\ \sf\longmapsto 0.83=\dfrac{P}{430}

\\ \sf\longmapsto P=430(0.83)

\\ \sf\longmapsto P\approx361m

  • P=Height of tower

5 0
2 years ago
Read 2 more answers
In the following diagram \overline{DE} \parallel \overline{FG}
Gnesinka [82]

Answer:

<x = 31°

Step-by-step explanation:

m<BCA = m<GCJ (vertical angles)

m<BCA = 59° (substitution)

Since line KL is perpendicular to line FG, the angle formed at point B is 90°.

Therefore, m<ABC = 90°

m<BAC + m<ABC + m<BCA = 180° (sum of triangle)

m<BAC + 90° + 59° = 180° (Substitution)

m<BAC + 149° = 180°

m<BAC = 180° - 149°

m<BAC = 31°

<x = <BAC (vertical angles)

m<x = 31° (substitution)

7 0
2 years ago
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