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2 years ago

Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.

Mathematics

2 answers:

DanielleElmas [232]2 years ago

8 0

Answer:

Step-by-step explanation:

Brums [2.3K]2 years ago

3 0

Answer:

sin(45°)= AC/9

cos(45°)= BC/9

Step-by-step explanation:

This is a right angle triangle:

∠ABC =∠CAB = 45°

Now

AC= CB

AB = 9 units.

We will apply sines:

sine(45°)= AC/AB

We know that AB = 9 units.

So substitute the value of side AB

sin(45°)= AC/9

Now apply cos(45°)

cos(45°)= BC/AB

Again substitute the value of AB:

cos(45°)= BC/9

Thus the answer is

sin(45°)= AC/9

cos(45°)= BC/9 ....

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Use the drop-down menus to choose steps in order to correctly solve 4k−6=-2k−16−2 for k .

Triss [41]

While there is no drop-down menu options for me to choose. I will show you how to solve this.

$\mathrm{Subtract\:the\:numbers:}\:-16-2=-18 \ \textgreater \ 4k-6=-2k-18$

$\mathrm{Add\:}6\mathrm{\:to\:both\:sides} \ \textgreater \ 4k-6+6=-2k-18+6 \ \textgreater \ Simplify$

$4k=-2k-12 \ \textgreater \ \mathrm{Add\:}2k\mathrm{\:to\:both\:sides} \ \textgreater \ 4k+2k=-2k-12+2k$

Simplify again.

$6k=-12 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}6 \ \textgreater \ \frac{6k}{6}=\frac{-12}{6} \ \textgreater \ Simplify \ \textgreater \ k=-2$

Hope this helps!

8 0

1 year ago

WILL MARK BRAINLIEST Enter the correct answer in the box. Write your answer in the form y = mx + b, using the appropriate inequa

frutty [35]

Answer:

y<-2x-3

Step-by-step explanation:

y∠mx+b

find the slope m : x=0, y=-3 (0,-3)

x=-3, y=3 (-3,3)

m=y2-y1/x2-x1

m=3-(-3)/-3-0

m=6/-3 =-2

y=-2x+b b=-3 when x=0, y=b

y<-2x-3

7 0

1 year ago

Read 2 more answers

By rewriting the formula for the Multiplication Rule, you can write a formula for finding conditional probabilities. The condit

ss7ja [257]

Answer:

89.01% probability that a flight arrives on time given that it departed on time.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Departing on time

Event B: Arriving on time.

The probability that a flight departs and arrives on time is 0.81.

This means that $P(A \cap B) = 0.81$

The probability that an airplane flight departs on time is 0.91.

This means that $P(A) = 0.91$

Find the probability that a flight arrives on time given that it departed on time.

$P(B|A) = \frac{0.81}{0.91} = 0.8901$

89.01% probability that a flight arrives on time given that it departed on time.

5 0

1 year ago

Toms math teacher asks 6 is 20 percent of what number tom incorrectly says 120 what’s is the correct number

Setler79 [48]

6=20% * n

6 = .20 * n

divide by .20

6/.2 = n

30 =n

Answer: 30

8 0

2 years ago

() and () are inverses of one another and drawn on the same graph with the same scale on both the horizontal and vertical axis.

Gelneren [198K]

Answer: Option A.

Step-by-step explanation:

We have the functions f(x) and g(x), that are inverses between them.

This means that if:

f(x) = y

then:

g(y) = x.

now, remember that:

When we have a point (x, y), and we reflect it over the line y = x, our new point will be (y, x).

So before we whe had:

f(x) = y.

and now in that same place, we have:

g(y) = x.

So the old graph of f(x) now coincides with the graph of g(x). (And the old graph of g(x) now coincides with the graph of f(x) )

So A is true.

B) This depends on the function:

if we have f(x) = x + 1.5

then f(0) = 1.5

now we want that:

g(1.5) = 0, then we can write:

g(x) = x - 1.5

Now f(x) and g(x) are inverses, and we would have that:

f(x) = g(x) + 3.

So f(x) is g(x) translated up by 3 units, but this is a particular case, not a general one, so B is not always true.

C and D) When we do rotations of 90° or 180°, we are effectively changing the quadrant of our point. so rotations will cause not only changes as the reflection over the x = y line, those will also cause changes in the sign of our variables, so, while for some functions f(x) and g(x) we can have that the rotations will map one into the other, this is not the general case.

6 0

1 year ago