Question

A study of consumer smoking habits includes 177 people in the 18-22 age bracket ( 48 of whom smoke), 146 people in the 23-30 age bracket ( 31 of whom smoke), and 81 people in the 31-40 age bracket ( 28 of whom smoke). If one person is randomly selected from this sample, find the probability of getting someone who is age 18-22 or does not smoke.

Answer 1

Answer:

The probability of getting someone who is age 18-22 or does not smoke is 0.854 ....

Step-by-step explanation:

Through the given statements we have to find the probability of getting someone who is age 18-22 or does not smoke.

Age 18-22 has 177 people. 48 of whom smoke.

People who does not smoke =(177-48) + (146-31) +(81-28)

People who does not smoke=129+115+53 = 297

People with age (18-22) who does not smoke = 129

P(18-22 or does not smoke) = (177+297-129)/(177+146+81)

P(18-22 or does not smoke) = 345/404

P(18-22 or does not smoke) = 0.854

Thus the probability of getting someone who is age 18-22 or does not smoke is 0.854 ....

Answer 2

The probability of getting someone who is age 18-22 or does not smoke is 0.44

Further explanation

Smoking is the practice when substance is burned and the resulting smoke breathed in to be tasted and absorbed into the bloodstream. Smoking tobacco is a physical addiction and a psychological habit. The probability is the measure quantifying the likelihood that events will occur.

A study of consumer smoking habits includes 177 people in the 18-22 age bracket ( 48 of whom smoke), 146 people in the 23-30 age bracket ( 31 of whom smoke), and 81 people in the 31-40 age bracket ( 28 of whom smoke). If one person is randomly selected from this sample.

Find the probability of getting someone who is age 18-22 or does not smoke.

Let event A = someone of age 18-22 and event B = someone who smokes. Then,

$P(A)=\frac{smokers of age 18-22 }{all people who have smoking habits} = \frac{177}{177+146+81} = \frac{177}{404}$

$P(B)=\frac{someone who smokes}{all people who have smoking habits} = \frac{48+31+28}{177+146+81} = \frac{107}{404}$

$P(AandB)=\frac{ smokers of age 18-22+someone who smokes}{all people who have smoking habits} = \frac{48}{177+146+81} = \frac{48}{404}$

Using the definition, we have:

$P(AorB)=P(A)+P(B)-P(AandB)=\frac{177}{400} +\frac{ 107 }{400} - \frac{48}{400} = \frac{176}{400}= \frac{11}{25}=0.44$

Therefore, the probability of selecting someone who is age 18-22 or smokes is 0.44

Learn more

1. Learn more about probability brainly.com/question/12029535
2. Learn more about age brainly.com/question/4229572
3. Learn more about smoke brainly.com/question/2632851

Answer details

Grade:          5

Subject:  Math

Chapter:  probability

Keywords:  smoke, probability, age, bracket, person