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2 years ago

For circle H, JN = 5, NK = 4, LN = 2 and NM = x. Solve for x

Mathematics

2 answers:

Ugo [173]2 years ago

6 0

Check the picture below.

Brut [27]2 years ago

3 0

Answer: The value of x = 10

Step-by-step explanation:

Given : For circle H, JN = 5, NK = 4, LN = 2 and NM = x.

We know that when two chords intersects each other then the product of their segments is equal.

For the given figure , we have

$JN\times NK=LN\times NM\\\\\Righatrrow\ 5\times4=2\times x\\\\\Rightarrow\ x=\dfrac{5\times4}{2}=10\\\\\Rightarrow\ x=10$

Hence, the value of x = 10

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Jackie walks into a convenience store and recognizes the number of lottery tickets she can purchase varies inversely with the pr

OLEGan [10]

Let the price of the tickets be 'x' and the number of tickets bought is 'y'

When the y inversely proportioned to x, the equation is

y = k/x where k is a constant

We work out the value of k by using the information y = 6 and x = 5

6 = k/5
k = 30

Hence, the maximum number of tickets when the price is $3 is

y = 30/3
y = 10 tickets

3 0

2 years ago

Read 2 more answers

Given the values of the linear functions f (x) and g(x) in the tables, where is (f – g)(x) positive?

alexandr402 [8]

Comparing the functions, from the tables, it is found that (f - g)(x) is positive in the interval (–∞, 9) .

----------------------

For the subtraction function, we simply subtract both functions, thus:

$(f - g)(x) = f(x) - g(x)$

It is positive if f is greater than g, that is: f(x) > g(x).
It is a linear function, so one function is greater before the equality, one after.
They are equal at x = 9.
If x < 9, f(x) > g(x), and thus, (f - g)(x) is positive, which means that the desired interval is:

(–∞, 9)

A similar problem is given at brainly.com/question/24610273

4 0

1 year ago

(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX

pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable X follows a Normal distribution with mean μ = 10 and variance σ² = 36.

(a)

Compute the value of P (X > 5) as follows:

$P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z$

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

$P(4$

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

$P(X$

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

$P(X$

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

$P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z$

Thus, the value of P (X > 16) is 0.1587.

**Use a z-table for the probabilities.

8 0

2 years ago

Luke and Lena's parents allow them to borrow against their allowances. The ineguality − $ 11.50 < − $ 10.75 compares the curr

Leto [7]

Answer:

$11.50

Step-by-step explanation:

I believe that $11.50 is the amount that Luke owes to his parents because their parents let them go beyond their allowances. Right now Luke is at debt for $-11.50 and has to pay their parents $11.50.

7 0

2 years ago

Match the following guess solutions yp for the method of undetermined coefficients with the second-order nonhomogeneous linear e

qaws [65]

Answer:

Step-by-step explanation:

For each of the yp(x) we can deduce the characteristic polynomial of the differential equation

$yp(x)=Ax^2+Bx+C\\m^2=0\\y''=0$