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2 years ago

Which of the following best describes the slope of the line below?

Mathematics

2 answers:

Scrat [10]2 years ago

5 0

Just in case:

This slope goes through (0,0) or more formally, the origin.

Lelu [443]2 years ago

3 0

Answer with explanation:

Equation of line passing through origin is given by

y=m x

As line passes through (5,-5) and (-5,5).

So, putting the value of ordered pair in above equation , to obtain slope

5=-5m

Dividing both sides by , -5 we get

m=-1

And equation of line is, y=-x, having slope equal to -1.

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The acceleration of an object due to gravity is 32 feet per second squared. What is acceleration due to gravity in inches per se

GarryVolchara [31]

For each foot there are 12 inches so we multiply by 12

32*12 = 384 inches

C

5 0

2 years ago

Read 2 more answers

The erea of a square is given by x2, where x is the length of one side. Mary's original garden was in the shape of a square. She

crimeas [40]

Answer: The expression that represents the area of Mary's new garden =2x^2

Step-by-step explanation:

The area of a square is given by x^2, where x is the length of one side. The length of the other side is also x. In a square, all sides are equal. each of the four sides equal x

Area = x × x

Area = x^2

She decided to double the area of her garden

New area = 2(x × x)

New area = 2x^2

The expression that represents the area of Mary's new garden =2x^2

7 0

2 years ago

On september 8, 2004, the genesis spacecraft crashed in the utah desert because its parachute did not open. the 210-kg capsule h

maw [93]

311km/h = 86.389 m/s
Initial KE 
= 0.5 * 210 * 86.389^2 J 

work done by force of ground 
= F * 0.81 J 

0.5 * 210 * 86.389^2 = 0.81 F 

F = 967433.58 N 

capsule's weight W= 210 * 9.81 = 2060.1 N 

F = 469.6 times capsule weight ---answer

6 0

2 years ago

One end of a 4ft iron rod is attached to the center of a pulley with radius of 0.5 ft. The other end is attached at a 40 degree

mr_godi [17]

We use the formula
L = rθ
where s is the arc length or the length of the wire
r is the distance from the center to the end of the rod
θ is the angle made by the rod with the wall

Substituting the values and converting the angle to radian measure
L = 4 (40°) (π/180°)
L = 2.79 feet

3 0

2 years ago

Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in

Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of Americans who decide to not go to college = 48%

n = sample of American adults = 331

p = population proportion of Americans who decide to not go to

college because they cannot afford it

Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.

So, 90% confidence interval for the population proportion, p is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\hat p-p$ < $1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

P( $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

90% confidence interval for p = [ $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ , $0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ ]

= [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$