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Lady bird [3.3K]

1 year ago

5

You and two friends visit a pizza shop. There are 15 toppings. 5 toppings are meat and the rest are vegetable. Each of you order

s a different topping (no repeats) at random. What is the probability that your group orders only meat toppings? please can anyone help me with this problem. ill give a medal

1 answer:

viktelen [127]1 year ago

4 0

Chance of u choosing meat is 5/15
first friend chooses, probability is 4/14
second friend chooses, probability is 3/13
so multiplying all 3 probablilities we get 2.2 percent

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A lumber yard has a scrap sheet of plywood that is 23 3/4 inches by 41 1/5 inches long what is the area of the plywood?

Sholpan [36]

Answer:

$978\frac{1}{2}\text{ inches}^2$ .

Step-by-step explanation:

We have been given that a lumber yard has a scrap sheet of plywood that is 23 3/4 inches by 41 1/5 inches long.

Since plywood is in shape of rectangle, so to find the area of plywood we will multiply the length of plywood by its width.

$\text{Area of rectangle}=\text{Length*Width}$

$\text{Area of plywood}=23\frac{3}{4}\text{ inches}\times 41\frac{1}{5}\text{ inches}$

Let us convert our mixed fractions into improper fractions.

$\text{Area of plywood}=\frac{95}{4}\text{ inches}\times \frac{206}{5}\text{ inches}$

$\text{Area of plywood}=\frac{95}{4}\times \frac{206}{5}\text{ inches}\times \text{inches}$

Upon cancelling out greatest common factors we will get,

$\text{Area of plywood}=\frac{19}{2}\times 103\text{ inches}^2$

$\text{Area of plywood}=\frac{1957}{2}\text{ inches}^2$

Now let us convert our answer into mixed fraction.

$\text{Area of plywood}=978\frac{1}{2}\text{ inches}^2$

Therefore, the area of plywood is $978\frac{1}{2}\text{ inches}^2$ .

8 0

2 years ago

the weight of a bag of golf balls varies directly as the number of golf balls in the bag.If a bag of 69 gold balls weighs 2,553

seropon [69]

Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

Then we have the following direct variation equation,

$\dfrac{x}{1110}=\dfrac{69}{2553}$

Multiply 1110 both sides , we get

$x=\dfrac{69}{2553}\times1110=30$

Hence, there are 30 balls in the bag.

4 0

1 year ago

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

mamaluj [8]

Answer:

The 95% confidence interval the average maximum power is (596.0 to 644.0)

Step-by-step explanation:

Average maximum of the sample = x = 620 HP

Standard Deviation = s = 45 HP

Sample size = n = 16

We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.

Degrees of freedom = df = n - 1 = 15

Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table = $t_{\frac{\alpha}{2}}$ = 2.131

The formula to calculate the confidence interval is:

$(x-t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} }, x+t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} })$

We have all the required values. Substituting them in the above expression, we get:

$(620-2.131 \times \frac{45}{\sqrt{16} }, 620+2.131 \times \frac{45}{\sqrt{16} })\\\\ =(596.0 , 644.0)$

Thus, the 95% confidence interval the average maximum power is (596.0 to 644.0)

7 0

2 years ago

A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports

hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

$t = 3.054$

4

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

5

The conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0

1 year ago

Matt Adams is the best player in his college baseball team. In his last few games, Matt has hit 70%, 77% 81% and 88% of balls th

Ksivusya [100]

79 is the answer ........

6 0

1 year ago

Read 2 more answers