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e-lub [12.9K]
2 years ago
12

A cereal company puts toys into 40% of its cereal

Mathematics
1 answer:
nalin [4]2 years ago
7 0

Answer:

I'd say D

Step-by-step explanation:

Because it makes the most sense and it is the most notable one.

Correct me if I'm wrong.

Hope this helps :).

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The average body mass index of children 9 years old is 18.4 with a standard deviation of 4.5. If it is known that the distributi
stellarik [79]

Answer:

Mass index for a 9-year-old child (at 82nd percentile ) = 22.51

Step-by-step explanation:

Given:

Mass index for a 9-year-old child  = 18.4

Standard deviation = 4.5

Find:

Mass index for a 9-year-old child (at 82nd percentile )

Computation:

At 82nd percentile,

p-value = 0.82

p-value from Z table score = 0.9153

Mass index for a 9-year-old child (at 82nd percentile ) = Mass index for a 9-year-old child + p-value from Z table score(Standard deviation)

Mass index for a 9-year-old child (at 82nd percentile ) = 18.4 + 0.9153(4.5)

Mass index for a 9-year-old child (at 82nd percentile ) = 18.4 + 4.11

Mass index for a 9-year-old child (at 82nd percentile ) = 22.51

6 0
2 years ago
Find x rounded to one decimal place.
8090 [49]
There is little information please state more points.
7 0
2 years ago
Read 2 more answers
In 2012, California had a population of about 38 million people, and North Dakota had a population of about 699,000 people. What
Gemiola [76]

Answer:

37,301,000

Step-by-step explanation:

The difference in population can be determined by subtracting the population of North Dakota from California

38,000,000 - 699,000 = 37,301,000

5 0
2 years ago
Explain how to find the product of 3/8 x 7/9 .Use complete sentences in your answer.
saw5 [17]

Answer:

When multiplying fractions together, you multiply the numerators togethers and the denominators together, unlike adding fractions together. To find this answer, you'd do 3 × 7 (for the numerator) and 8 × 9 (for the denominator), and then write the fraction (the answer) using your answers above.

I hope this helps!

7 0
2 years ago
A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

7 0
2 years ago
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