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2 years ago

7

Jon and Jim are cutting a log Jon cut 1/5 of the log on one end while Jim cut 2/9 of the log on the other side.How much of the l

og is left

2 answers:

Mandarinka [93]2 years ago

8 0

26/45 Of The Log Is Remaining ..

Nuetrik [128]2 years ago

5 0

There is 26/45 of the log left.

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A rectangle that had the perimeter of 70 and the area of 250 has enlarged; its sides became twice as long. what is the new area

aliya0001 [1]

The perimeter of the original rectangle is:
P = 2w + 2l = 70
The area of the original rectangle is:
A = w * l = 250
Then, by modifying the length of its sides we have:
Perimeter:
P '= 2 (2w) +2 (2l)
Rewriting:
P '= 2 (2w + 2l)
P '= 2P
P '= 2 (70)
P '= 140
Area:
A '= (2w) * (2l)
Rewriting:
A '= (2) * (2) (w) * (l)
A '= 4 * w * l
A '= 4 * A
A '= 4 * 250
A '= 1000
Answer:
the new area and the new perimeter are:
P '= 140
A '= 1000

3 0

2 years ago

Ibrahim has some building blocks that are all cubes of the same size. He uses three of the blocks to make a pile with a height o

MArishka [77]

Answer:

72.5

Step-by-step explanation:

one block = 43.5 / 3 = 14.5

five blocks = 5 * 14.5 = 72.5 (ans)

4 0

2 years ago

Anja is creating a triangle using three straws. The two shorter straws have lengths of 20 cm and 21 cm. How long, in centimeters

Digiron [165]

A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm

3 0

2 years ago

Consider this equation: –2x – 4 + 5x = 8 Generate a plan to solve for the variable. Describe the steps that will be used.

horrorfan [7]

We are given the function <span>–2x – 4 + 5x = 8 and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:

-2x + 5x =8+4
Then, do the necessary operations.

3x = 12
x = 4.
The variable x has a value of 4.</span>

6 0

2 years ago

Read 2 more answers

jose is choosing a 3-letter password from the letters a,b,c,d. the password cannot have the same letter repeated in it. how many

kvasek [131]

Alright, so we are dealing with permutations. Permutations are the number of combinations in a specific order possible for the set.

There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:

$_{n}P_{r}= \frac{n!}{(n-r)!}$

$r=$ number of elements in the subset

$n=$ number of elements in the set

$P=$ permutations of the set

There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.

Here's the math:

$_{n}P_{r}= \frac{n!}{(n-r)!}$

$_{4}P_{3}= \frac{4!}{(4-3)!}$

$_{4}P_{3}= \frac{4!}{(1)!}$

$_{4}P_{3}= \frac{4(3)(2)(1)}{1}$

$_{4}P_{3}=24$

There are 24 permutations. I can prove this by showing you the model:

ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.

Hope this helps!

Answer: 24 passwords are possible

5 0

2 years ago