Ask question

Ask question

All categories

Dennis_Churaev [7]

2 years ago

9

Paul, Kevin, Justin, and David will share the cost of buying a fishing boat.

1 answer:

Gnom [1K]2 years ago

8 0

Paul = 2550*.2 = 510

Kevin = 2550*.25 = 637.5

Justin = 2550*.3 = 765

David = 2550-510-637.5-765 = 637.5

You might be interested in

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

2 years ago

if BD is perpendicular to AC M angle DBE equals 2x - 1 + m angle CBE equals 5x - 42 find the value of x

Paha777 [63]

<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

I've drawn a graph in order to a better understanding of this problem. We know that:

BC is perpendicular to AC

∠DBE = 2x - 1

∠CBE = 5x - 42

Let's call the intersection of line BC and AC the point P, so:

∠P=90°

And points B, P and C form the triangle ΔBPC. On the other hand, ∠CBE and ∠PCB are Alternate Interior Angles, so:

∠PCB = ∠CBE = 5x - 42

Moreover:

∠PBC = 2x - 1 - (5x - 42)

∠PBC = 2x - 1 - 5x + 42

∠PBC = -3x + 41

The internal angles of any triangle add up to 180°. Hence for ΔBPC:

90° + ∠PBC + ∠PCB = 180°

90° - 3x + 41 + 5x - 42 = 180°

2x + 89 = 180

2x = 91

x = 45.5°

7 0

2 years ago

The area of a square is stored in a double variable named area. write an expression whose value is length of the diagonal of the

lbvjy [14]

First of all, a bit of theory: since the area of a square is given by

$A = s^2$

where s is the length of the square. So, if we invert this function we have

$s = \sqrt{A}$ .

Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

$d = \sqrt{s^2+s^2} = \sqrt{2s^2} = s\sqrt{2}$

So, the diagonal is the side length, multiplied by the square root of 2.

With that being said, your function could be something like this:

double diagonalFromArea(double area) {

double side = Math.sqrt(area);

double diagonal = side * Math.sqrt(2);

return diagonal;

}

3 0

2 years ago

A pond had 60 fish. 27 were carp and the rest were tench. 10 fish were added. The probability that a fish picked at random is a

ivanzaharov [21]

Answer: 2

<u>Explanation:</u>

A pond had 60 fish but 10 were added so now the pond has 70 fish.

The probability of choosing a carp is 1/2 so $\frac{1}{2} (70)$ = 35 are now carp.

There were 27 carp and now there are 35 carp so 8 carp were added.

10 fish were added and 8 of them were carp so 2 of them were tench.

6 0

2 years ago

FIRST ONE TO ANSWER GETS BRAINLIEST Henry divided his socks into five equal groups. Let s represent the total number of socks. W

Alex777 [14]

Answer: There are 20 socks in the first case and there are 75 socks in the second case.

Step-by-step explanation:

Since we have given that

Number of equal groups = 5

Let the total number of socks be 's'.

According to question, expression will be

Now, Suppose number of socks in each group = 4

So, it will become,

Suppose number of socks in each group = 15

So, Total number of socks become

Hence, there are 20 socks in the first case and there are 75 socks in the second case.

3 0

2 years ago