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SIZIF [17.4K]
2 years ago
11

Miguel and his brother Ario are both standing 3 meters from one side of a 25-meter pool when they decide to race. Miguel offers

Ario a head start. Miguel says he will start when the ratio of Ario's completed meters to Ario's remaining meters is 1:4. How many meters will Ario swim before Miguel starts the race? Round to the nearest tenth. meters
Mathematics
1 answer:
Westkost [7]2 years ago
3 0

Answer:

Miguel start to swim when Ario has traveled 4.4 m.

Step-by-step explanation:

The total lenght of the pool is 25.

Since both of them standing 3 m from one side of the pool, then, the total distance both need to cover is 25-3 m= 22 m.

Assume that the distance traveled by Ario before Miguel start to swin is x. That means, the remaining distance to Ario (to cover the total size of the pool) is 22-x.

Then, in acoordance to the problem, the ratio between these two distances must be equal to 1/4.

That is,

\frac{x}{22-x}=\frac{1}{4} .

So, we need to obtain x from this equation. We must note that x\neq 22, otherwise we have a zero in the denominator.

So, we rearrange the equation,

4x=22-x (Multiplying both sides of equation by (4(22-x)).

Then, 5x=22.

Therefore, x=4.4 m.

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One. Kamala.

Step-by-step explanation:

7 0
1 year ago
Meghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount of th
kupik [55]

Answer:

67 eghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount

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4 0
2 years ago
The decay of 192 mg of an isotope is given by A(t)= 192e-0.015t, where t is time in years. Find the amount left after 55 years.
statuscvo [17]

Answer:

This is a typical radioactive decay problem which uses the general form:

A = A0e^(-kt)

So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

A = 192e^(-0.015*55)

A = 84 mg

6 0
2 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
2 years ago
What integer is equivalent to 25 3/2
antiseptic1488 [7]
<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

<u>Explanation</u>
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
</span></span>
3 0
1 year ago
Read 2 more answers
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