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Pavel [41]
2 years ago
9

A plant foreman wanted to know how many hours had been spent on a particular project. He asked his supervisors to report the hou

rs worked by each department. Here’s the information he received. Department A. . . . . . . . . . . . . . . . . . . . . . . . . . .202.5 hours
Department B . . . . . . . . . . . . . . . . . . . . . . . . . . 212 3⁄4 hours
Department C . . . . . . . . . . . . . . . . . . . . . . . . . .198.25 hours
Department D. . . . . . . . . . . . . . . . . . . . . . . . . . .215 1⁄5 hours
Calculate the total number of hours spent on this project by all four departments. (Hint: Change all the hours to either decimals or fractions before adding.)
Mathematics
2 answers:
yan [13]2 years ago
5 0

Answer:

828.7 hours

Step-by-step explanation:

We have the following data:

Department A. . . . . . . . . . . . . . . . . . . . . . . . . . .202.5 hours

Department B . . . . . . . . . . . . . . . . . . . . . . . . . . 212 3⁄4 hours

Department C . . . . . . . . . . . . . . . . . . . . . . . . . .198.25 hours

Department D. . . . . . . . . . . . . . . . . . . . . . . . . . .215 1⁄5 hours

Note that the hours recorded in department B and D are written in the form of a mixed number

Before making the sum we must convert the mixed numbers into decimal form

Then we add the main number with the fraction that accompanies it

Department\ B = 212\ \frac{3}{4}\ hours =212+\frac{3}{4} = 212.75\ hours\\\\Department\ D=215\ \frac{1}{5}\ hours=215 + \frac{1}{5} = 215.2\ hours

Finally the total hours are:

202.5 + 212.75 + 198.25+215.2=828.7\ hours

anygoal [31]2 years ago
3 0

Answer:

828.7 hours.

Step-by-step explanation:

To answer a question in which the total time has to be calculated of all the activities, first of all, all the times have to be converted to a single form. There are two types: decimals and fractions. Convert the fractions into decimals.

Department A = 202.50 hours.

Department B = 212 3⁄4 hours  = 212.75 hours.

Department C = 198.25 hours.

Department D = 215 1⁄5 hours = 215.20 hours.

Therefore, the total number of hours spent on this project by all four departments. is the sum of all the above numbers. 202.50 hours + 212.75 hours + 198.25 hours + 215.20 hours = 828.7 hours.

Therefore, the total time is 828.7 hours!!!

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Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in
Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                         P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of Americans who decide to not go to college = 48%

           n = sample of American adults = 331

           p = population proportion of Americans who decide to not go to

                 college because they cannot afford it

<em>Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.</em>

<em />

<u>So, 90% confidence interval for the population proportion, p is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                        of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.645) = 0.90

P( -1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \hat p-p < 1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

P( \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

<u>90% confidence interval for p</u> = [ \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } } , 0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } } ]

 = [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error =  Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

              0.015 = 1.645 \times \sqrt{\frac{0.48(1-0.48)}{n} }

              \sqrt{n}  = \frac{1.645 \times \sqrt{0.48 \times 0.52} }{0.015}

              \sqrt{n} = 54.79

               n = 54.79^{2}

               n = 3001.88 ≈ 3002

Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

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AlexFokin [52]

Answer: 32

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1. cos of 58 deg= 0.529919264

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agasfer [191]

Answer:

  J Darren earns $17.35 per hour at his job. How many hours does he need to work in order to earn more than $624.60?

Step-by-step explanation:

You're looking for a situation in which the number 17.35 needs to be multiplied by an unknown quantity.

Scenarios F and G involve addition of 17.35 to something.

Scenario H would correspond to the inequality ...

  17.65x < 624.60

The sign of the given inequality is >, so scenario H is not the one.

__

In scenario J, Darren's total earnings for x hours will be 17.35x, and we want to find x such that this total is greater than 624.60. This matches the given inequality:

  17.35x > 624.60 . . . . . . answer choice J

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2 years ago
How should the decimal point in 6.093 be moved to determine the product of 1,000 × 6.093?
drek231 [11]

Answer:

3 positions to the right.

Step-by-step explanation:

1000 * 6.093

= 6093.

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2 years ago
In Andrew’s Furniture Shop, he builds bookshelves and tables. Each type of furniture takes him about the same time to make. He f
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A. You may set the variables in either order. But for argument sake, let's set as follows:

x = Amount of bookshelves
y = Amount of tables

B. Because of the amount of things you need to make, the following is an inequality using those variables.

x + y > 25

Plus you can determine a second inequality based on the amount of money that you have to spend. 

20x + 45y < 675

Finally you may also add in that each value must be greater than or equal to zero, since they cannot have negative tables. 

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(0,0)
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