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Burka [1]
2 years ago
9

The lifeguards at the beach post information of surfers by placing 3 flags, one above the other, on a flag pole. If there are 7

different flags available, how many possible signals can be flown?
Mathematics
2 answers:
ozzi2 years ago
5 0

Answer: 210

Step-by-step explanation:

Given : The number of flags available = 7

The number of flags required = 3

Since for the arrangement of flags , the order matters.

So we apply permutation to find the number of possible signals.

The number of possible signals of 7 flags taking 3 at a time is given by :-

^7P_3=\dfrac{7!}{(7-3)!}=\dfrac{7\times6\times5\times4!}{4!}=210

Hence, the number of possible signals of 7 flags taking 3 at a time is  210

Mazyrski [523]2 years ago
3 0

Hello! The answer to your question would be as followed:

The amount of possible signals that can be shown is 210.

7^p3

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Find the distance from (4, −7, 6) to each of the following.
LenKa [72]

Answer:

(a) 6 units

(b) 4 units

(c) 7 units

(d) 9.22 units

(e) 7.21 units

(f) 8.06 units

Step-by-step explanation:

The distance d from one point (x₁, y₁, z₁) to another point (x₂, y₂, z₂) is given by;

d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Now from the question;

<em>(a) The distance from (4, -7, 6) to the xy-plane</em>

The xy-plane is the point where z is 0. i.e

xy-plane = (4, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, -7, 0)</em>

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Hence, the distance to the xy plane is 6 units

<em>(b) The distance from (4, -7, 6) to the yz-plane</em>

The yz-plane is the point where x is 0. i.e

yz-plane = (0, -7, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 6)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Hence, the distance to the yz plane is 4 units

<em>(c) The distance from (4, -7, 6) to the xz-plane</em>

The xz-plane is the point where y is 0. i.e

xz-plane = (4, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 6)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 6)²]

d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Hence, the distance to the xz plane is 7 units

<em>(d) The distance from (4, -7, 6) to the x axis</em>

The x axis is the point where y and z are 0. i.e

x-axis = (4, 0, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 0)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x axis is 9.22 units

<em>(e) The distance from (4, -7, 6) to the y axis</em>

The x axis is the point where x and z are 0. i.e

y-axis = (0, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 0)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

d = √[(4)² + (6)²]

d = √[(16 + 36)]

d = √(52)

d = 7.22

Hence, the distance to the y axis is 7.21 units

<em>(f) The distance from (4, -7, 6) to the z axis</em>

The z axis is the point where x and y are 0. i.e

z-axis = (0, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, 0 6)</em>

d = √[(4 - 0)² + (-7 - (0))² + (6 - 6)²]

d = √[(4)² + (-7)² + (0)²]

d = √[(4)² + (-7)²]

d = √[(16 + 49)]

d = √(65)

d = 8.06

Hence, the distance to the z axis is 8.06 units

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2 years ago
alon has $175 and needs to save at least $700 for a new computer. If he can save $35 per week, what is the minimum number of wee
soldier1979 [14.2K]
700 - 175 is equal to 525 when you divide that by 35 you get 15 which is your answer.
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2 years ago
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Is it possible to draw three lines in two planes such that all three lines are skew?
nata0808 [166]
Yes; it is possible 

<span>If the planes are parallel to each other then they don't intersect. </span>

<span>There can also be two or more lines on different planes which do not intersect each other. These lines are called skew lines.</span>
8 0
2 years ago
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some species of bacteria can copy their DNA and divide every 40 minutes. If a COLONY of 100 of these such bacteria begins with a
VikaD [51]

Answer:

The answer is 51,200 bacterium.

Step-by-step explanation: So you need to figure out the time between 12 and 6pm, then divide it by 40. 12-6 is 360 minutes, you divide by 40 and you get 9 divisions. Multiply the 100 x 2=200, 200 x 2 =400, and so on for 9 times.

You get a result of 51,200 bacterium.

8 0
1 year ago
The physician tells a woman who usually drinks 5 cups of coffee daily to cut down on her coffee consumption by 75%. If this woma
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1 cup=8 ounces

5*8=40

Each day the women drinks 40 oz of coffee.

40oz-75%=10oz

Thus, if the women complies to the physician's instructions, she can drink 10oz or about 1.25 cups of coffee daily.

4 0
2 years ago
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