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Burka [1]
1 year ago
9

The lifeguards at the beach post information of surfers by placing 3 flags, one above the other, on a flag pole. If there are 7

different flags available, how many possible signals can be flown?
Mathematics
2 answers:
ozzi1 year ago
5 0

Answer: 210

Step-by-step explanation:

Given : The number of flags available = 7

The number of flags required = 3

Since for the arrangement of flags , the order matters.

So we apply permutation to find the number of possible signals.

The number of possible signals of 7 flags taking 3 at a time is given by :-

^7P_3=\dfrac{7!}{(7-3)!}=\dfrac{7\times6\times5\times4!}{4!}=210

Hence, the number of possible signals of 7 flags taking 3 at a time is  210

Mazyrski [523]1 year ago
3 0

Hello! The answer to your question would be as followed:

The amount of possible signals that can be shown is 210.

7^p3

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must a function that is decreasing over a given interval always be negative over that same interval explain
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check the picture below.


notice, a function that is decreasing, namely  have a negative slope, doesn't have to be negative.

8 0
2 years ago
Read 2 more answers
1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas d
TiliK225 [7]

Answer:

1. The amount that was not spent is: 1080 soles

2. The answer is 5.

Step-by-step explanation:

Question 1. There are two situations:

If you spent 5/8 of the money then notice, that u did not spend 3/8.

If you spend 2/5 of the money, then you would have 72 more.

So think, this equation:

3/8x + 72 = 2/5x

2/5 of the money is the value for what you did not spend plus 72, the amount you would have, where x is the answer for the total of money.

72 = 2/5x - 3/8x

72 = 1/40x

x = 2880 soles

As you did not spend 3/8 of 2880, the answer is 1080 soles

Notice that if u spent 2/5 of 2880, you would have 1152 soles, so, the 1080 + 72, as the problem said.

Question 2.

We think letters for this excersise.

N = My born year

2020 (this year) - N = E (my age, now)

So N + 10 = when I get 10 years old

N + 20 = when I get 20 years old

N + 30 = when I get 30 years old

N + 40 = when I get 40 years old

The problem says:

(N+10) + (N+20) - (N+E) = 2020

((N+30)+E) - (N-40) = X  

So if 2020 - N = E, then notice that 2020 - E = N. Let's replace this in the equation form:

((2020-E)+10) + ((2020-E)+20) - ((2020-E)+E) = 2020

No minus in the first two terms, so we can break the ( )

2020-E+10 + 2020-E+20 - ((2020-E)+E) = 2020

We apply the distributive property for the second term

2020-E+10 + 2020-E+20 - 2020+E-E = 2020

We can cancel two E, and the 2020, so the new form will be:

2020 - 2E + 30 = 2020

We can also cancel the 2020, so if we reorder the equation, we have:

-2E = -30

E = 15 That's my age, so my born's year is 2020 - 15 = 2005 (N)

Look:

(2005 + 10) + (2005+20) - (2005+15) = 2020

So now, the last part

((2005+30)+15) - (2005+40) = 5

3 0
1 year ago
Employment data at a large company reveal that 74% of the workers are married, 42% are college graduates, and that 56% are marri
ValentinkaMS [17]

Answer:

(E) None of these above are true.

Step-by-step explanation:

Married = 74% or 0.74

College graduates = 42% or 0.42

pr(married | college graduates) = 0.56

(A) These events are pairwise disjoint. This is false. Pairwise disjoint are also known as mutually exclusive events. Here we can see that both events are occurring at same time.

(B) These events are independent events. This is also false.

(C) These events are both independent and pairwise disjoint. False

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Here Probability(A or B) shall be 1

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This is not equal to 1.

(E) None of these above are true. This is true.

8 0
2 years ago
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Total profit $234.00
5 0
2 years ago
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Answer:

$550

Step-by-step explanation:

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If you divide both sides by 400, you'll get x=5.5

Next, multiply 5.5 by $100 because each group gives $100

hope this helps!

4 0
1 year ago
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