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Arte-miy333 [17]
2 years ago
10

The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. Although

it requires a successful completion of three levels of grueling exams, it also entails promising careers with lucrative salaries. A student of finance is curious about the average salary of a CFA® charterholder. He takes a random sample of 49 recent charterholders and computes a mean salary of $150,000 with a standard deviation of $35,000. Use this sample information to determine the 90% confidence interval for the average salary of a CFA charterholder. Assume that salaries are normally distributed.
Mathematics
1 answer:
Nastasia [14]2 years ago
7 0

Answer:  ($141,775, $158,225)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.9=0.1

Critical value : z_{\alpha/2}=1.645

Sample size : n= 49

Sample mean : \overline{x}=150,000

Standard deviation : \sigma=35,000

The confidence interval for population mean is given by :_

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

= 150,000\pm (1.645)\dfrac{35000}{\sqrt{49}}\\\\\approx150,000\pm8225\\\\=(150,000-8225,150,000+8225)=(141,775,158,225)

Hence,he 90% confidence interval for the average salary of a CFA charter-holder = ($141,775, $158,225)

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Answer:

c

Step-by-step explanation:

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2 years ago
Tony’s class needs more than $500 for the school dance. So far, they have raised $200. They plan to have a car wash, charging $8
anzhelika [568]
<h2><em><u>PLZ MARK BRAINLIEST</u></em></h2><h2><em><u></u></em></h2>

No, he is not correct for if they washed 37 cars they would have made a total of 296 dollars washing cars. Because this is an inequality, he needs to get a value equal too or greater than 300 dollars on car washes. Also, because he already has 200 dollars collected, you could write the inequality as "8x is greater than or equal to 300".

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2 years ago
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The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. H
Lina20 [59]

The arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

<em><u>Explanation</u></em>

The given formula is:   s=V_{0}t-16t^2

If the initial velocity is 96 ft/s , that means  V_{0}=96

For finding the time the arrow takes to reach a height of 48 ft, we will plug s= 48 into the above formula. So......

48=96t-16t^2\\ \\ 16t^2-96t+48=0\\ \\ 16(t^2-6t+3)=0\\ \\ t^2-6t+3=0\\ \\ t^2-6t =-3\\ \\ t^2-6t+9=-3+9\\ \\ (t-3)^2 = 6\\ \\ t-3= \pm \sqrt{6} \\ \\ t=3\pm \sqrt{6}\\ \\ t = 5.45 , 0.55

So, the arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

7 0
2 years ago
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If →u and →v are the vectors below, find the vector →w whose tail is at the point halfway from the tip of →v to the tip of →v−→u
S_A_V [24]
Û = (-1, -1, -1)
^v = (2, 3, -5)
^v - û = (2 + 1, 3 + 1, -5 + 1) = (3, 4, -4)
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Halfway from û to ^v = ((2 + 1)/2, (3 + 1)/2, (-5 + 1)/2) = (3/2, 2, -2)

The required vector ^w = ((3/2 - 1/2), (2 - 1/2), (-2 - 1/2)) = (1, 1/2, -5/2)
5 0
2 years ago
Upgrading a certain software package requires installation of 68 new files. Files are installed consecutively. The installation
ser-zykov [4K]

Answer:

The probability that the whole package is uppgraded in less then 12 minutes is 0,1271

Step-by-step explanation:

The mean distribution for the length of the installation (in seconds) of the programs will be denoted by X. Using the Central Limit Theorem, we can assume that X is normal (it will be pretty close). The mean of X is 15 and the variance is 15, hence, the standard deviation is √15 = 3.873.

We want to find the probability that the full installation process takes less than 12 minutes = 720 seconds. Then, in average, each program should take less than 720/68 = 10.5882 seconds to install. Hence, we want to find the probability of X being less than 10.5882. For that, we will take W, the standariation of X, given by the following formula

W = \frac{X-\mu}{\sigma} = \frac{X-15}{3.873}

We will work with \phi , the cummulative distribution function of the standard Normal variable W. The values of \phi can be found in the attached file.

P(X < 10.5882) = P(\frac{X-15}{3.873} < \frac{10.5882-15}{3.873}) = P(W < -1,14)

Since the density function of a standard normal random variable is symmetrical, then \phi(-1.14) = 1-\phi(1.14) = 1-0.8729 = 0.1271

Therefore, the probability that the whole package is uppgraded in less then 12 minutes is 0,1271.

Download pdf
7 0
2 years ago
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