Answer:
"NOT lookup
" is the correct approach.
Explanation:
- This methodology significantly reduces the quantity of congestion of DNS messages on a certain file. The application establishes that whenever a question reaches if it is processed. Unless the file is loaded, then perhaps the response is returned with the cached cache.
- Typically the name resolution occurs in something like a DNS File. The conversion usually occurs throughout this cycle from Username to IP, including IP via Username.
Answer:
5, 10 and 16
Explanation:
The sum of their ages is √961 = 31
If Joe is x years old, the equation that follows is:
x + (x+5) + (x+5+6) = 31
This simplifies to
3x = 31 - 11 - 5 = 15
so x=5
From that you can find
Joe = x = 5
Kate = x+5 = 10
Jody = x+5+6 = 16
Answer:
Occipital bone-atlas
Explanation:
The occipital bone is a bone that covers the back of your head; an area called the occiput. The occipital bone is the only bone in your head that connects with your cervical spine (neck). The occipital bone surrounds a large opening known as the foramen magnum.
The foramen magnum allows key nerves and vascular structures passage between the brain and spine. Namely, it is what the spinal cord passes through to enter the skull. The brainstem also passes through this opening.
The foramen magnum also allows 2 key blood vessels traversing through the cervical spine, called the vertebral arteries, to enter the inner skull and supply blood to the brain
Solution :
class Employee:
#Define the
#constructor.
def __
__(
, ID_number, 
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
