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marin [14]
2 years ago
5

The recommended weight of a soccer ball is 430 grams. The actual weight is allowed to vary by up to 20 grams. a. Write and solve

an absolute value equation to find the minimum and maximum acceptable soccer ball weights. Use xx as the variable.
Mathematics
1 answer:
elixir [45]2 years ago
3 0

Answer:  |x-430|≤20

Step-by-step explanation:

Let's call x₀=430grams and let's call δ= 20grams. So x₀

is the recommended weight but it is allowed to vary + or - 20 grams. We can see it as an interval of real numbers whose center is 430 and whose ratio is 20.

If we solve this inequation we will obtain  -20≤ x-430≤20.

If we add both sides 430, we will obtain -20+430≤x≤430+20.

This will be mean that the weight vary from 410grams to 450 grams.

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37 For a class picnic, two teachers went to the same store to purchase drinks. One teacher purchased 18 juice boxes and 32 bottl
Pavel [41]

Answer:

Step-by-step explanation:

Let j represent the cost of a juice box.

Let w represent the cost of a bottle of water.

One teacher purchased 18 juice boxes and 32 bottles of water, and spent $19.92.. This means that

18j + 32w = 19.92 - - - - - - - - - - - - 1

The other teacher purchased 14 juice boxes and 26 bottles of water, and spent $15.76. This means that

14j + 26w = 15.76- - - - - - - - - - - - 2

Multiplying equation 1 by 14 and equation 2 by 18, it becomes

252j + 448w = 278.88

252j + 468w = 283.68

Subtracting, it becomes

- 20j = - 4.8

j = - 4.8/- 20 = 0.24

Substituting j = 0.24 into equation 1, it becomes

18 × 0.24 + 32w = 19.92

4.32 + 32w = 19.92

32w = 19.92 - 4.32 = 15.6

w = 15.6/32 = 0.4875

Kara's prices are incorrect.

the cost of a juice box is $0.24

the cost of a bottle of water is $0.4875

7 0
2 years ago
Work out the probability that halima at least walks one way
ANEK [815]
Can you please explain what you said
8 0
2 years ago
What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

= 1/2 *r²*3(π/180 β)

= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE =\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}

= 4/3

7 0
2 years ago
Read 2 more answers
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ValentinkaMS [17]
The answers for edunuity are 1,3,5,6 you're welcome.
3 0
2 years ago
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A candy manufacturer makes two types of special candy, say A and B. Candy A consists of equal parts of dark chocolate and carame
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If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
a + c = x
2b + d = y
a + 2b ≤ 360
c ≤ 430
d ≤ 210
P = 285x + 260y

This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
6 0
2 years ago
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