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maria [59]
2 years ago
12

In a 4 3/5 mile race, there are two water stations. The first water station is 1/3 of the way from the starting point. The secon

d water station is 2/3 of the way from the starting point. How far is the first water station to the second water station?
Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

The difference between the first water station and the second would be 1/3 of the total mile distance.

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Masha is making a scale diagram of the front face of an aquarium. The face is shaped like a rectangle.
Marat540 [252]
Scale:
1 cm : 6 inches

---------------------------------
Length of the aquarium:
---------------------------------
5 feet = 5 x 12 = 60 inches
60 ÷ 6 = 10 
The length will be 10 cm on the scale drawing.

---------------------------------
Width of the aquarium:
---------------------------------
2 feet = 2 x 12 = 24 inches
24 ÷ 6 = 4 

The width will be 4 cm on the scale drawing.

---------------------------------
Find Perimeter:
---------------------------------
Perimeter = 2 (length + width)
Perimeter = 2( 10 + 4 )
Perimeter = 28 cm

--------------------------------------------------------------------------------------------------
Answer:  The perimeter of the scale drawing of the front face is 28 cm.--------------------------------------------------------------------------------------------------

4 0
2 years ago
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Anne states that reflections preserve side lengths, so PN 2 PN. PM apo, and MNON, therefore the triangles are congruent.
Neporo4naja [7]

Answer:

Only Anne

Step-by-step explanation:

7 0
2 years ago
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Yasmin has a bag containing 165 colored beads. Her classmates take turns selecting one bead from the bag without looking, record
adell [148]

Answer:

30 , 45 , 51 , 39

Step-by-step explanation:

You just add up the numbers until you get 165

5 0
2 years ago
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Find c, yenvelope(x,t), and ycarrier(x,t). express your answer in terms of a, k1, k2, x, t, ω1, and ω2. separate the three parts
steposvetlana [31]

Answer:

C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )

Step-by-step explanation:

Given

Y_1(x,t)=A \sin(K_1x- \omega _1 t)\\\\Y_2(x,t)=A \sin(K_2x- \omega _2 t)

using a trigonometrical identity

sin p + sin q = 2 sin ( p+q/2) cos ( p-q/2)

and here the condition is

the choice is in between sinax and cosax

where a > b

so we get using above equation

C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )

4 0
2 years ago
You want to paint a piece of pottery at an art studio. The total cost is the cost of the piece plus an hourly studio fee. There
Nataly_w [17]
Answer:
3 hours

Explanation:
1) Set an expression for each of the studios we can set out variable as h for hours because that is the unknown value.

Studio A: 10+8h
Studio B: 16+6h

To find out how many hours would pass for their costs to equal each other, we have to make them literally equal each other.

10+8h=16+6h

Now that we have an equation, we can start solving.

10+8h=16+6h
Combine like terms
10-16=6h-8h
-6=-2h
2h=6
Divide both sides by 2 to isolate h
2h/2=6/2
h=3

I hope this helped! If it did, a brainliest would be much appreciated :)
5 0
2 years ago
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