This is an example of lack of self management. Dianne is experiencing lack of self management, which resulted in a difficult time adjusting her stroke when playing tennis because she's used to playing badminton.
Hope this helps. - M
a. A translation stop codon is added at the 3' end of the pre-mRNA.
c. A poly-A tail (50-250 adenine nucleotides) is added to the 3' end of the pre-mRNA.
d. Coding sequences called exons are spliced out by ribosomes.
Explanation:
In eukaryotes, during protein synthesis, the RNA must exit nucleus through the pores on the nuclear membrane and enter into the cytoplasm to undergo translation.
The exit processes of mRNA are: the 5’ capping, 3’ Poly-A tail, and pre-mRNA splicing.
The 5’capping is the initial step with addition of 7-methylguanosine cap to the 5’ end of the mRNA by phosphate linkage. This process protects the mRNA from degrading and helps to initiate translation processes.
The 3’ Poly-A tail step is the cleaving of pre-mRNA and addition of addition of around 200 A nucleotides or the 3’poly (A) tail to the mRNA by the poly (A) polymerase enzyme protein complex. This prevents pre-mRNA degradation, facilitates movement of mRNA to the cytoplasm, and initiates translation.
Pre-mRNA splicing is done to remove the introns from the mRNA because they are not part of function protein coding. The exons which take part in protein coding sequence are spliced once the introns are excised.
Finally, the resultant mRNA will exit the nucleus and enter the cytoplasm to undergo translation
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Answer:
The healthcare professionals can help equalize the unequal partnership between the adult patient and the provider by using preventive care services and promoting communication that can be directed to an institutional culture that normalizes appropriate assertive responses to stereotyping and ratifying adult patient’s life experience through health care personnel training. With this, they can educate both adult patient and the provider to become more mindful of cues that induce stereotypical thinking.
HOPE IT HELPS!!!
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Out of the following
A. .08 BAL per hour
B. .05 BAL per hour
C. .018 BAL per hour
D. .015 BAL per hour
The answer is D. This is equivalent to 0.015 g / 100mL / hour leaving your body after alcohol intake. This occurs after the alcohol is broken down by the liver to acetaldehyde and then to acetic acid by alcohol dehydrogenase (ADH). The acetic acid is later excreted through the kidneys and skin. On average, the liver can metabolize 1 ounce of alcohol every hour. It takes approximately 5.5 hours for 0.08 ounces of alcohol to leave the system after intake.
