Keith has 40-pound bags of mulch in his truck that weigh a total of 3600 pounds. His Owner’s Manual lists the truck’s capacity a
1 answer:
Answer:
Keith must remove 90-75 = 15 bags in order to meet the weight requirements
Step-by-step explanation:
This problem can be solved by consecutive rules of three problem.
Rule of three problem:
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, the measures are:
- The number of bags
- The total weight
As the number of bags increases, so do the total weight. So, the relationship between the measures is direct.
To know how many bags does Keith need to remove in order to meet the weight requirements, we first need to know how many bags are in the truck currently.
The problem states that each bag weighs 40 pounds and the weight of the truck is 3600 pounds, so:
1 bag - 40 pounds
x bags - 3600 pounds
40x = 3600
x = 90.
Keith currently has 90 bags in the truck.
Now, we have to know how much bags he can have in the truck, that is, 3000 pounds worth of bags. So:
1 bag - 40 pounds
x bags - 3000 pounds
40x = 3000
x = 75.
The truck's capacity is at most 75 bags.
So, Keith must remove 90-75 = 15 bags in order to meet the weight requirements
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Answer:
1
2
3
Step-by-step explanation:
Generally when two fair 6-sided dice is rolled the doubles are
(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)
The total outcome of doubles is N = 6
The total outcome of the rolling the two fair 6-sided dice is
n = 36
Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as
Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is
(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)
Looking at this outcome we see that there are two doubles present
So
The conditional probability that doubles were rolled is mathematically represented as
Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30
And the number of outcomes that at least one die is a 1 is W = 10
So
The conditional probability that at least one die is a 1 is mathematically represented as
=>
=>
Answer:
6 units
Step-by-step explanation:
Given: Points H and F lie on circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.
To find: Length of GH.
Sol: EC = CH = 9 (Radius of the same circle are equal)
Now, GC = GH + CH
GC = GH + 9
Now In ΔEGC, using pythagoras theorem,
......(ΔEGC is a right triangle)
Now, Let GH = <em>x</em>
On rearranging,
So x = 6 and x = - 24
∵ x cannot be - 24 as it will not satisfy the property of right triangle.
Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.