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kozerog [31]
2 years ago
13

Two players A and B play a marble game. Each player has both a red and blue marble. They present one marble to each other. If bo

th present red, A wins $3. If both present blue, A wins $1. If the colors of the two marbles do not match, B wins $2. Is it better to be A, or B, or does it matter?
Mathematics
1 answer:
levacccp [35]2 years ago
5 0

Answer:

Step-by-step explanation:

A has one red and blue marble and B has one red and blue marble.

Hence selecting one marble is equally likely with prob = 0.5

Since A and B are independent the joint event would be product of probabilities.

Let A be the amount A wins.

If each selects one, the sample space would be

             (R,R)  (R,B)  (B,R) (B,B)

Prob     0.25  0.25  0.25  0.25

A              3       -2     -2       1

E(A)      0.75   -0.5    -0.5   0.25   =    0

The game is a fair game with equal expected values for A and B.

It does not matter whether to be A or B

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Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t
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IQR = Q_3 -Q_1 = 28-18 = 10

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b. 3

Step-by-step explanation:

For this case we have the following summary:

Minimum = 9 represent the minimum value

Q_1 = 18 represent the first quartile

Median =Q_2= 21 represent the median

Q_3 = 28 represent the third quartil

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If we use the 1.5 IQR we need to find first the interquartile range defined as:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

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So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

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2 years ago
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The quadratic formula, has a part we call the "discriminant" defined by the variables that are inside the square root, and is denotated by "delta":

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