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Contact [7]
2 years ago
11

On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne

gative 2), and point S is at (negative 3, 2). In the diagram, SR = 4 StartRoot 2 EndRoot and QR = StartRoot 10 EndRoot. What is the perimeter of parallelogram PQRS? StartRoot 10 EndRoot units 8 StartRoot 2 EndRoot + 2 StartRoot 10 EndRoot units 16 StartRoot 2 EndRoot units 8 StartRoot 2 EndRoot + 8 units
Mathematics
2 answers:
skad [1K]2 years ago
4 0

Answer:

B

Step-by-step explanation:

Anika [276]2 years ago
3 0

Answer:

The perimeter of parallelogram PQRS = 2\sqrt{10}+8\sqrt{2} ⇒

2nd answer

Step-by-step explanation:

* <em>Lets revise some properties of the parallelogram</em>

- Each two opposite sides are parallel

- Each two opposite sides are equal

- Its <em>perimeter</em> is the <em>twice the sum of two adjacent sides</em>

* <em>Lets solve the problem</em>

∵ PQRS is a parallelogram

∵ The length of side SR is 4\sqrt{2}

∵ The length of side QR is \sqrt{10}

∵ <em>SR and RQ are two adjacent sides</em>

∵ The perimeter of parallelogram PQRS = 2(RQ + SR)

∴ The perimeter of parallelogram PQRS = 2(\sqrt{10}+4\sqrt{2})

∵ 2*\sqrt{10} = 2\sqrt{10}

∵ 2*4\sqrt{2} = 8\sqrt{2}

∴ The perimeter of parallelogram PQRS = 2\sqrt{10}+8\sqrt{2}

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