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krek1111 [17]
2 years ago
14

A test tube contains 25 bacteria, 5 of which are can stay alive for atleast 30 days, 10 of which will die in their second day. 1

0 of which are already dead.
Given that a randomly chosen bacteria for experiment is alive. What is the probability it will still be alive after one week?
(a)1 ⁄ 3(b)2 ⁄3
(c) 1⁄5 (d)4 ⁄5
Mathematics
1 answer:
boyakko [2]2 years ago
3 0

Answer:

c. \frac{1}{5}

Step-by-step explanation:

Given,

Number of bacterias who alive for at least 30 days = 5,

Bacterias who alive for 2 days = 10,

Died bacterias = 10,

Total bacterias = 5 + 10 + 10 = 25,

Ways of choosing a bacteria = ^{25}C_1 = \frac{25!}{1! 24!} = 25,

While, ways of choosing of a bacteria who will live after 1 week = ^5C_1 = \frac{5!}{1!4!} = 5,

Hence, the probability it will still be alive after one week = \frac{5}{25} = \frac{1}{5}

OPTION C is correct.  

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----------------------------------------------

Work Shown:

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