Louis Rahn is currently earning an annual salary of $25,090 at Budgett

Mathematics

1 answer:

Doss [256]2 years ago

7 0

Answer:

$30.19

Step-by-step explanation:

find out how much he works per week at each place by dividing each anual sallary by 52

subtract tthe first weekly sallary from the second weekly salary.

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The equation 1.5r + 15 = 2.25r represents the number r of movies you must rent to spend the same amount at each movie store. how

EleoNora [17]

1.5r+15=2.25r
First of all, you have to arrange the numbers according to those similar to them. So that will be;
15=2.25r-1.5r
1.5r is subtracted from 2.25r because it crossed over an equality sign to get its position close to 2.25r. And when a number crosses over an equality sign, the sign on the number chages to the opposite. 1.5r has an invisible positive sign which became negative when it crossed. Anyway;
2.25r-1.5r is the same as 2.25-1.5. And that is 0.75r
Therefore;
15=0.75r
To find out what r is, you have to divide the both sides by 0.75. This is done to remove the 0.75 close to r to finally reveal what r is. Anyway;
15/0.75=0.75r/0.75
15 divided by 0.75 is 20. And 0.75r divided by 0.75 is r. So;
20=r
r=20. So the answer is 20 movies. Hope i helped. Have a nice day.

4 0

2 years ago

A health food company sells packs of assorted nuts. The company incurs a monthly fixed cost of $1,400 for ingredients and raw ma

tino4ka555 [31]

If you're asking about what the equation would be written as, then it's y = 1x + 1,400.

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2 years ago

Read 2 more answers

Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\

motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in $\sqrt{7}$ , $1 - \sqrt{6}$ and -3. The last root gives us the factor (x+3). Hence, our polynomial is

$P(x) =(x+3)q(x)$

where $q$ is a polynomial with rational coefficients and roots $\sqrt{7}$ and $1 - \sqrt{6}$ . The root $\sqrt{7}$ gives us a factor $x-\sqrt{7}$ , but in order to obtain rational coefficients we must consider the factor $x^2-7$ .

An analogue idea works with $1 - \sqrt{6}$ . For convenience write $x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}$ . This gives the factor $(x-1)^2-6$ . Hence,

$P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105$

Notice that $P(-1)=24$ . So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

$P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35$

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type $x-\sqrt7$ will introduce in the expression, we need to multiply by its conjugate $x+\sqrt7$ . Hence, we will obtain $x^2-7$ that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.