A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as a control chart.
Answer:
1,500
Step-by-step explanation:
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
Answer:
The two stadiums are approximately 3115.1 meters away from each other
Step-by-step explanation:
Since we can construct two right angle triangles between the blimp and the two stadiums as shown in the attached image, then the distance "x" between the two can be find as the difference between the right triangle legs that extend on the ground.
In order to find the size of such legs, one can use the tangent function of the given depression angles as shown below:
and for the other one:
The the distance between the stadiums is the difference:
b - a = 3405.7 - 290.6 meters = 3115.1 meters
Insufficient information.
The construction of many regular polygons has this sequence as a starting point, including square, pentagon, octagon, decagon, and others. Jonas could also be construcing an isosceles right triangle with hypotenuse equal to the diameter of the circle.
