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myrzilka [38]
2 years ago
3

Ernesto, the magnificent unicorn stallion, covered a distance of 50 kilometres on his first trip to Zalsazaria. On a later trip,

he travelled 300 kilometres while going three times as fast. What was his new time compared with the old time?
Mathematics
1 answer:
andrey2020 [161]2 years ago
6 0

Answer: The new time was twice as long as the old time.

Step-by-step explanation:

By definition:

t=\frac{d}{V}

Where "t" is time, "V" is speed and "d" is distance.

We know that Ernesto covered a distance of 50 kilometers on his first trip to Zalsazaria. This is:

t_1=\frac{50}{V}

On the later trip, he travelled 300 kilometers and he was going three times as fast (3V), then:

t_2=\frac{300}{3V}

Knowing this, we can compare those times:

\frac{t_1}{t_2}=\frac{\frac{50}{V}}{\frac{300}{3V}}\\\\\frac{t_1}{t_2}=\frac{150V}{300V}\\\\\frac{t_1}{t_2}=\frac{1}{2}

Solving for t_2 we get:

t_1=\frac{1}{2}*t_2\\\\t_2=2t_1

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Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:
svp [43]

Answer:

Option B. w=5h-8

Step-by-step explanation:

we have

h=(\frac{1}{5})w+(\frac{8}{5})

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

5h=w+8

subtract 8 both sides

5h-8=w+8-8

5h-8=w

Rewrite

w=5h-8

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2 years ago
A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la
nikdorinn [45]

Answer:

f(x) = 3(2)^x

Step-by-step explanation:

The Table is:

<u>x</u>    <u>f(x)</u>

-2   3/4

-1    3/2

0    3

1     6

2    12

The exponential funtion has the next form:

f(x) = a(b)^x

At x = 0, f(x) = a. Then, a = 3

Isolating b from the equation:

f(x)/a = b^x

ln(f(x)/a) = x*ln(b)

[ln(f(x)/a)]/x = ln(b)

At x = 1, f(x) = 6. Then:

[ln(6/3)]/1 = ln(b)

ln(2) = ln(b)

2 = b

Therefore, the function is f(x) = 3(2)^x

7 0
2 years ago
Drag each expression to show whether it is equivalent to
Kazeer [188]

Answer:

We need to find which expressions are equivalent to 6(c+6), 6c+6 or neither.

6c+12: We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

6c+12=+(c+2)

Therefore, this expression is equivalent to neither of the given expressions.

2(3c+3): We just need to apply the distributive property.

2(3c+3)=6c+6

Therefore, this expression is equivalen to 6c+6.

We use the same process to the other expressions.

(6c)+(6\times 6)=6c+36=6(c+6)

3c+6+3c=6c+6

6c+36=6(c+6)

(6+c)+(6+6)=c+18, equivalent to neither.

7 0
2 years ago
If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
Gala2k [10]

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

mHMK=\frac{1}{2}(mJL+mHLK)

On putting the values in the above formula, we get

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

On applying cross-multiplication, we get

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

On subtracting "18x" from both sides, we get

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

On adding "2" both sides, we get

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

So that mHLK = (204)°

4 0
2 years ago
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