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ollegr [7]
2 years ago
7

Noah drew a scaled copy of Polygon P and labeled it Polygon Q. If the area of Polygon P is 5 square units, what scale factor did

Noah apply to Polygon P to create Polygon Q?

Mathematics
2 answers:
vredina [299]2 years ago
8 0

Answer:

The scale factor is 3

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

x -----> area of polygon Q

y ----> area of polygon P

so

z^{2}=\frac{x}{y}

we have

y=5\ units^2

<em>Find the area of polygon Q</em>

Divide the polygon Q into five squares

see the attached figure N 2

The area of polygon Q (area of the  five squares)  is

x=5(3^2)=45\ units^2

<em>Find the scale factor</em>

z^{2}=\frac{x}{y}

we have

x=45\ units^2

y=5\ units^2

substitute

z^{2}=\frac{45}{5}

z^{2}=9

square root both sides

z=3

therefore

The scale factor is 3

Svetach [21]2 years ago
5 0

Answer:

3 is the answer

Step-by-step explanation:

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The answer would be 1.6666666668
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2 years ago
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Identify the equation of the circle that has its center at (-27, 120) and passes through the origin.
nasty-shy [4]
<h3><u>The equation of the circle that has its center at (-27, 120) and passes through the origin is</u>:</h3>

(x + 27)^2 + (y - 120)^2 = 15129

<em><u>Solution:</u></em>

<em><u>The equation of a circle is given as:</u></em>

(x-a)^2+(y-b)^2=r^2

Where,

(a, b) is the centre of the circle

r is the radius

We have the centre of the circle (-27, 120)

Therefore,

a = -27

b = 120

Given that, it passes through origin. which means, (x, y) = (0, 0)

Substitute (a, b) = (-27, 120) and (x, y) = (0, 0) in eqn

(0 + 27)^2 + (0 - 120)^2 = r^2\\\\729 + 14400 = r^2\\\\r^2 = 15129

Substitute r^2 = 15129 and (a, b) = (-27, 120) in eqn

(x + 27)^2 + (y - 120)^2 = 15129

Thus the equation of circle is found

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2 years ago
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In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

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