All categories

2 years ago

A parcel has a mass of 500g. Calculate its weight. (Assume the gravitational field strength is 10N/kg).

Mathematics

1 answer:

Elan Coil [88]2 years ago

5 0

Answer:

The weight of the parcel is 5 N

Step-by-step explanation:

we know that

Weight can be calculated using the equation:

$W=mg$

where

W ----> weight (W) is measured in newtons (N)

m ----> mass (m) is measured in kilograms (kg)

g ----> gravitational field strength (g) is measured in newtons per kilogram (N/kg)

In this problem we have

$g=10\ N/kg$

$m=500\ g$

Remember that

$1\ kg=1,000\ g$

To convert g to kg

Divide by 1,000

$m=500\ g=500/1,000=0.5\ kg$

substitute the values in the equation

$W=(0.5)(10)=5\ N$

therefore

The weight of the parcel is 5 N

You might be interested in

As part of Kayla's exercise program,she either runs 6miles/day or rides her bike 10 miles/day.Her new goal is to cover a minimum

poizon [28]

6(15) + 10b > = 200
90 + 10b > = 200
10b > = 200 - 90
10b > = 110
b > = 110/10
b > = 11

so she can do 15 days of running plus 11 days of biking....which totals 26 days

8 0

2 years ago

a sports statistician claim that the mean winning times for boston marathon women's open division champions is at least 2.68 hou

GenaCL600 [577]

Answer:

We conclude that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

Step-by-step explanation:

We are given that a sports statistician claim that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

The mean winning time of a sample of 30 randomly selected Boston marathon women's open division champions is 2.60 hours. assume the population standard deviation is 0.32 hours.

Let $\mu$ = mean winning times for Boston marathon women's open division champions.

So, Null Hypothesis, $H_0$ : $\mu\geq$ 2.68 hours {means that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours}

Alternate Hypothesis, $H_A$ : p < 2.68 hours {means that the mean winning times for Boston marathon women's open division champions is less than 2.68 hours}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean winning time = 2.60 hours

$\sigma$ = population standard deviation = 0.32 hours

n = sample of women's open division champions = 30

So, test statistics = $\frac{2.60-2.68}{\frac{0.32}{\sqrt{30} } }$

= -1.37

The value of z test statistics is -1.37.

Now, P-value of the test statistics is given by following formula;

P-value = P(Z < -1.37) = 1 - P(Z $\leq$ 1.37)

= 1 - 0.9147 = 0.0853

Since, P-value of the test statistics is more than the level of significance as 0.0853 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

6 0

2 years ago

Johanna will plant up to 32 acres on her farm with wheat and corn. Fewer than 11 acres will be planted with wheat

konstantin123 [22]

What exactly is the question?

3 0

1 year ago

The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in

Marina86 [1]

Answer:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

$\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3$