Answer:
Sammy needs to use a program and design the ad using density independent pixels.
Explanation:
Based on the scenario being described within the question it can be said that in the future Sammy needs to use a program and design the ad using density independent pixels. This will allow the design to correctly scale up and down by adding the correct ration or pixels needed so that the image is always as clear as originally intended. This will prevent such scenarios as this one.
Answer:
Regency Bank
A = $98577.46
king Bank
A = $81832.68
Explanation:
Given Data:
principle amount =$ 5000
rate of interest = 15%
n =12 {compounded months}
t = 20 year
for Regency Bank
investment amount obtained as
![A =P\times [1 + \frac{r}{n}]^{nt}](https://tex.z-dn.net/?f=A%20%3DP%5Ctimes%20%5B1%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%5D%5E%7Bnt%7D)
![A = 5000 [1 + \frac{0.15}{12}]^{12\times 20}](https://tex.z-dn.net/?f=A%20%3D%205000%20%5B1%20%2B%20%5Cfrac%7B0.15%7D%7B12%7D%5D%5E%7B12%5Ctimes%2020%7D)
A = $98577.46
for King Bank
Investment amount obtained as
![A =P\times [1 + \frac{r}{n}]^{nt}](https://tex.z-dn.net/?f=A%20%3DP%5Ctimes%20%5B1%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%5D%5E%7Bnt%7D)
Here n = 1
![A = 5000 [1 + \frac{0.15}{1}]^{1\times 20}](https://tex.z-dn.net/?f=A%20%3D%205000%20%5B1%20%2B%20%5Cfrac%7B0.15%7D%7B1%7D%5D%5E%7B1%5Ctimes%2020%7D)
A = $81832.68
Answer: A) Fair value of the asset(s) given up.
Explanation:
Non-monetary exchange occurs when non-financial assets are exchanged in a transaction. Recording this transaction is based on the fair value of the assets exchanged and the recording is usually done in one of 3 ways being,
1. At the fair value of the asset transferred in exchange for it with a gain or loss on the exchange being recorded.
2. At the fair value of the asset received, if the fair value of this asset is more evident than the fair value of the asset transferred in exchange for it.
3. At the recorded amount of the surrendered asset, if no fair values are determinable or the transaction has no commercial substance.
If you need any clarification do comment.
Answer:
P.Ed at p = 5 :- 0.26
Revenue maximising price = 8.5 ; Maximum Total Revenue = 1222
Explanation:
Price Elasticity of Demand shows responsive change in demand, due to change in price. P.Ed = ( dq / dp ) x ( p / q )
q = 216 - p^2
dq / dp = - 2p
P.Ed = dq / dp x ( p / q )
So, PEd = ( -2p ) x ( p / q )
[ (- 2p) (p) ] / [ 216 - p^2 ]
(- 2p^2 ) / ( 216 - p^2 )
Putting value of P = 5 in P.Ed
<u>- 2(25) </u>
216 - 25
= - 50 / 191
P.Ed = 0.26
Revenue is the total value of receipts from sale of goods & services. TR = p x q
q = 216 - p^2
TR = 216p - p^3
To find price maximising TR , we will derivate TR function with respect to 'p'
d TR / d p = 216 - 3p^2
d TR / d p = 216 - 3p^2 = 0
3p^2 = 216
p^2 = 216 / 3
p^2 = 72
p = √ 72
p = 8.5
Finding maximum revenue ; Putting price = 8.5 in TR function
TR = 216p - p^3
216 (8.5) - (8.5)^3
1836 - 614
1222