Answer:
15*1.99
7*2.50
Step-by-step explanation:
I think you would multiply them (im not sure im not very good with math if its wrong im really sorry hope you get it though good luck :) ! )
Answer: If Ana produce more furge and Leo produce more toffee.
Step-by-step explanation:
Comparative advantage: A country or a person has a comparative advantage in producing a commodity if the opportunity cost of producing that commodity is lower in that country as compared to the other country.
Here Ana or Leo will gain comparative advantage only when they are selling the good they are specializing in and they would specialize in that good which would have lower opportunity cost for them.
(a) For Ana who devoted all of her time to making either 3 pounds of fudge or 2 pounds of toffee,
the opportunity cost for making 1 pound of furge is = 2/3 = 0.66
the opportunity cost for making 1 pound of toffee is = 3/2 = 1.5
(b) For Leo who devoted all of her time to making either 4 pounds of fudge or 5 pounds of toffee,
the opportunity cost for making 1 pound of furge is = 5/4 = 1.25
the opportunity cost for making 1 pound of toffee is = 4/5 = 0.8
Above calculations clearly shows that Ana has a comparative advantage in producing furge because opportunity cost of making furge is lower than the Leo, so he devotes most of his time to produce furge.
Whereas Leo has a comparative advantage in producing Toffee because opportunity cost of making toffee is lower than the Ana, so he devotes most of his time to produce toffee.
To find 20% of 950 you would set it up as a proportion. When doing percentages the prevent is always out of 100 so the first step would be 20/100. You are trying to find a number out of 950 so the second part would be ?/950. Now you want to cross multiply and divide. 20*950=19,000 then you divide it by 100 (your other number) 19,000/100=190. So 20% of 950 is 190.
3x² - 7x - 8 = 0
We're asked about square roots so we won't try to factor; we'll go right for the quadratic formula,
x = ( 7 ± √(7² - 4(3)(-8)) )/(2(3)) = (7 ± √(49+96))/6 = 7/6 ± √145/6
145 = 5×29, so no square factors. The positive difference is
d = (7/6 + √145/6) - (7/6 - √145/6) = 2√145/6 = √145/3
so m=145, n=3 for a sum of
Answer: 148
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :
Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...
The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)
The probability that among ten students in a class, at least two of them share a birthday is 0.002.
