answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leonid [27]
2 years ago
12

Brittany just pulled up a database table with employee information that contains 50 records of employees at her company. Which o

f the following terms best fits what she sees?
Schemas

Architecture

Instances

Operations
Computers and Technology
1 answer:
lesantik [10]2 years ago
3 0

Answer:

The answer is: Operations.

Explanation:

A database operation accesses to information of a relational database. In this case, Brittany has creates the database operation that select employee information of her company and the database has returned a result set. The SQL statement to perform operations on a database are:

  • INSERT
  • SELECT
  • UPDATE
  • DELETE

You might be interested in
A painting company has determined that for every 115 square feet or wall space, one gallon of paint and eight hours of labor wil
Kay [80]

The program to calculate the total paint cost and other values is given below.

#include <iostream>

using namespace std;

int main() {  

 int rooms, laborChrg = 18;

 float paintChrg;

 float feetPerRoom[rooms];  

 float paintReq, laborHrs, paintCost, laborCost, totalCost, totalsqft=0;  

 cout<<"Enter the number of rooms to be painted "<<endl;

 cin>>rooms;  

 for(int i=0; i <= rooms; i++)

 {

 cout<<"Enter the square feet in room "<<endl;

 cin>>feetPerRoom[i];  

 // shortcut operator which is equivalent to totalsqft = totalsqft +     feetPerRoom[i];

 totalsqft += feetPerRoom[i];

 }  

 cout<<"Enter the cost of the paint per gallon "<<endl;

 cin>>paintChrg;  

 laborHrs = (totalsqft/115)*8;

 laborCost = laborHrs * laborChrg;  

 paintReq = totalsqft/115;

 paintCost = paintReq * paintChrg;  

 totalCost = laborCost + paintCost;  

 cout<<"The number of gallons of paint required "<<paintReq<<endl;

 cout<<"The hours of labor required "<<laborHrs<<endl;

 cout<<"The cost of the paint is "<<paintCost<<endl;

 cout<<"The labor charges are "<<laborHrs<<endl;

 cout<<"The Total cost of the paint job is "<<totalCost<<endl;  

 return 0;

}

Explanation:

The header files for input and output are imported.

#include <iostream>

using namespace std;

All the variables are taken as float except labour charge per hour and number of rooms.

The user is asked to input the number of rooms to be painted. An array holds the square feet in each room to be painted.

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;  

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];  

totalsqft += feetPerRoom[i];

}  

The above code asks for square feet in each room and calculates the total square feet to be painted simultaneously.

All the data to be displayed is calculated based on the values of labor charge per hour and gallons of paint needed, given in the question.

laborHrs = (totalsqft/115)*8;

laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

All the calculated values are displayed in the mentioned order.

7 0
2 years ago
After deploying a large number of wireless laptop computers on the network, Taylor, the IT director at Contoso, Ltd. decides to
LenKa [72]

Answer:

Setting of short lease time for IP addresses in order to enhance quicker access from clients

6 0
2 years ago
EVERYONE LISTEN!!!! PLEASE COPY THIS MESSAGE AND RESEND!!!!
slavikrds [6]
Ok we will do it for you cause they are very mean
4 0
2 years ago
Read 2 more answers
The groups_per_user function receives a dictionary, which contains group names with the list of users. Users can belong to multi
Akimi4 [234]

The groups_per_user function receives a dictionary, which contains group names with the list of users.

Explanation:

The blanks to return a dictionary with the users as keys and a list of their groups as values is shown below :

def groups_per_user(group_dictionary):

   user_groups = {}

   # Go through group_dictionary

   for group,users in group_dictionary.items():

       # Now go through the users in the group

       for user in users:

       # Now add the group to the the list of

         # groups for this user, creating the entry

         # in the dictionary if necessary

         user_groups[user] = user_groups.get(user,[]) + [group]

   return(user_groups)

print(groups_per_user({"local": ["admin", "userA"],

       "public":  ["admin", "userB"],

       "administrator": ["admin"] }))

3 0
2 years ago
Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo
kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int n,no_open=0;

   cout<<"enter the number of lockers:";

   // read the number of lockers

   cin>>n;

   // initialize all lockers with 0, 0 for locked and 1 for open

   int lock[n]={};

   // toggle the locks

   // in each pass toggle every ith lock

   // if open close it and vice versa

   for(int i=1;i<=n;i++)

   {

       for(int a=0;a<n;a++)

       {

           if((a+1)%i==0)

           {

               if(lock[a]==0)

               lock[a]=1;

               else if(lock[a]==1)

               lock[a]=0;

           }

       }

   }

   cout<<"After last pass status of all locks:"<<endl;

   // print the status of all locks

   for(int x=0;x<n;x++)

   {

       if(lock[x]==0)

       {

           cout<<"lock "<<x+1<<" is close."<<endl;

       }

       else if(lock[x]==1)

       {

           cout<<"lock "<<x+1<<" is open."<<endl;

           // count the open locks

           no_open++;

       }

   }

   // print the open locks

   cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0
2 years ago
Other questions:
  • U.S. industries like steel, computers, and energy need to be protected from foreign competition to ensure which of the following
    6·2 answers
  • If you want to present slides to fellow students or coworkers which productivity software should you use to create them A. Word
    14·2 answers
  • Which of these is an advantage of using the Clipboard task pane? A. You are able to apply OLE easily. B. There are more paste op
    15·2 answers
  • Under what category of programs and apps do databases and enterprise computing fall?
    8·1 answer
  • Assume that the reference variable r refers to a serializable object. Write code that serializes the object to the file ObjectDa
    8·1 answer
  • You are attempting to open a file containing a list of integer numbers, each on a separate line, and read them into Python as in
    6·1 answer
  • What level of fault is the following example: North Lake Hospital followed all of the HIPAA policies and procedures for securing
    12·2 answers
  • In your own words, describe what Internet Protocols are. Why is it important to have agreed upon protocols?
    6·1 answer
  • c Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in a
    10·1 answer
  • Ryan has made a presentation of ten slides, which he wants to display in sequence after a specific time interval. Which element
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!