Question

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = y minus 4 equals StartFraction one-fourth EndFraction left-parenthesis x minus 9 right-parenthesis.(x – 8). What is the slope-intercept form of the equation for this line? y = y equals StartFraction one-fourth EndFraction x minus 12.x – 12 y = y equals StartFraction one-fourth EndFraction x minus 4.x – 4 y = y equals StartFraction one-fourth EndFraction x plus 2.x + 2 y = y equals StartFraction one-fourth EndFraction x plus 6.x + 6

Answer 1

Answer:

Third option: $y= \frac{1}{4}x+2$

Step-by-step explanation:

The correct form of the exercise is: "The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is $y -4 = \frac{1}{4}(x -8)$. What is the slope-intercept form of the equation for this line?"

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

Given the equation of the line in Point-Slope form:

$y -4 = \frac{1}{4}(x -8)$

You need to solve for "y" in order to write the given equation of the line in Slope Intercept form.

Then, this is:

$y -4 = \frac{1}{4}(x -8)\\\\y-4= \frac{1}{4}x-\frac{8}{4}\\\\y-4= \frac{1}{4}x-2\\\\y= \frac{1}{4}x-2+4\\\\y= \frac{1}{4}x+2$

You can identify that the slope "m" is:

$m=\frac{1}{4}$

And the y-interecept "b" is:

$b=2$

Answer 2

Answer:

c

Step-by-step explanation: