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anyanavicka [17]

1 year ago

5

kabir spends 1/3of his pocket money on books,1/5on traveling and rest on food.if his pocket money is 450 rupees how much money d

oes he spend on food?

1 answer:

Talja [164]1 year ago

4 0

Answer:

210

Step-by-step explanation:

450 X 1/3 = 150

450 X 1/5 = 90

.

90 + 150 = 240

.

450 - 240 = 210

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Alexandra and her children went into a grocery store and she bought $7.65 worth of

zalisa [80]

Answer:

$\large \boxed{\text{3 apples and 6 bananas}}$

Step-by-step explanation:

Let a = the number of apples

And b = the number of bananas. Then,

$\begin{array}{rcll}(1) \, 1.75a + 0.40 b & = & 7.65&\\(2)\, \, \, \, \quad \qquad a + b & = &9&\\(3) \, 0.40a + 0.40b & = &3.60&\text{Multiplied (2) by 0.40}\\1.35a & =&4.05\\(4) \, \, \quad \qquad \qquad a & =& \mathbf{3}&\text{Divided each side by 1.35}\\3 + b & = &9& \text{Substituted(4) into (2)}\\b &=& \mathbf{6}&\text{Subtracted 3 from each side}\\\end{array}\\\text{They bought $\large \boxed{\textbf{3 apples and 6 bananas}}$}$

Check:

$\begin{array}{cccl}3(1.75) + 6(0.40) = 7.65 & \qquad & 3 + 6 = 9\\5.25 + 2.40 = 7.65 & \qquad & 9 = 9\\7.65 = 7.65 & \qquad & \\\end{array}$

OK.

3 0

1 year ago

Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0

2 years ago

Find the additive inverse of 6-3i.

puteri [66]

Hey there!

In order to find the additive inverse of any number, regardless if it is real or not, you can simply multiply the number by -1 or negate it.

This should look like this:
-(6-3i)
=-6+3i

Therefore, the additive inverse of 6-3i is -6+3i.

**Note: Keep in mind, when the additive inverse of a number is added to the number, the number equals 0:
(6-3i)+(-6+3i)=0

Hope this helps and have a marvelous day! :)

5 0

1 year ago

Egbert is making trail mix out of 18 bags of nuts and 9 bags of dried fruit. He wants each new portion of trail mixto be identic

Over [174]

Answer:

2 bags of deezznuts and 1 bag of fruit

Step-by-step explanation:

18 bags of nuts

9 bags of fruit

2 bags of nuts mixed with 1 bag of fruit, multiply that by nine and you have no remainder on any of the bags

8 0

1 year ago

Igloos Unlimited charges $150 per night, with a 50% discount every night after the third night. If you stay for eight nights, ho

stiks02 [169]

Answer: (150x3)+((150/2)x5)=(450)+((75)x5)=450+375=825. You would have to pay $825.

5 0

1 year ago