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maxonik [38]
2 years ago
8

1. Technician A says that an automotive

Engineering
1 answer:
Mrrafil [7]2 years ago
3 0

Answer:

DNeither A nor B.

onefits of

Explanation:

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A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 3.5 mm (0.14 in
RideAnS [48]

To resolve this problem we have,

R=3.5mm\\F_f1=950N\\L_1=50mm\\b=12mm\\L_2=40mm

F_{f2} is unknown.

With these dates we can calculate the Flexural strenght of the specimen,

\sigma{fs}=\frac{F_{f1}L}{\pi R^3}\\\sigma{fs}=\frac{(950)(50*10^{-3})}{\pi 3.5*10^{-3}}\\\sigma{fs}=352.65Mpa

After that, we can calculate the flexural strenght for the square cross section using the previously value.

\sigma{fs}=\frac{F_{f2}L}{\pi R^3}\\(352.65*10^6)=\frac{3Ff(40*10^{-3})}{2(12*10^{-10})}\\F_{f2}=\frac{352.65*10^6}{34722.22}\\F_{f2}=10156.32N\\F_{f2}=10.2kN

6 0
2 years ago
If water molecules pass through a membrane with a steady state flux of 220 mole/(m2 day), how long will it take, in hours, for 0
goblinko [34]

Answer:

<em>0.0386 hr</em>

<em></em>

Explanation:

Area = 565 cm^2 = 0.0565 m^2  (1 cm^2 = 0.0001 m^2)

flux state rate = 220 mole/m^2-day

<em>There are 24 hrs in a day,</em> therefore rate in hrs will be

220/24 = 9.17 mole/m^2-hr

mass of water = 0.4 kg

molar mass of water = (1 x 2) + 16 = 18 kg/mole

therefore,

<em>mole of water = mass of water/molar mass of water</em>

mole of water = 0.4/18 = 0.02 mole

<em>mole flux = mole/area</em> = 0.02/0.0565 = 0.354 mol/m^2

<em>time that will be taken will be for water to pass = mole flux/mole flux rate</em>

time = 0.354/9.17 = <em>0.0386 hr</em>

7 0
2 years ago
CHALLENGE ACTIVITY 1.4.1: Basic syntax errors. Type the statements. Then, correct the one syntax error in each statement. Hints:
Lunna [17]

Answer:

Lets check each statement for the errors.

Explanation:

System.out.println("Predictions are hard.");

This statement has no syntax errors. When this statement is executed the following line will be displayed:

Predictions are hard.

System.out.print("Especially ');

This statement is missing the closing quotation mark. A single quotation mark is placed instead of double quotation mark in the statement.

The following error message will be displayed when this program statement will be compiled:

Main.java:15: error: unclosed string literal

String literals use double quotes. So to correct this syntax error, the statement should be changed as follows:

System.out.print("Especially");

The output of this corrected line is as following:

Especially

System.out.println("about the future.").

In this line a period . is placed at the end of the statement instead of a semicolon ; but according to the syntax rules statements should end in semicolons.

The error message displayed when this line is compiled is as following:

Main.java:15: error: ; expected

Main.java:15: error: not a statement

So in order to correct this syntax error the statement should be changed as following:

System.out.println("about the future.");    

The output of this corrected line is as following:

about the future

System.out.println("Num is: " - userName);

There is a syntax error in this statement because of - symbol used instead of +

+ symbol is used to join together a variable and a value a variable and another variable in a single print statement.

The error message displayed when this line is compiled is as following:

Main.java:13: error: bad operand types for binary operator '-'

So in order to correct this syntax error the statement should be changed as following:

System.out.println("Num is: " + userName);

This line will print two things one is the string Num is and the other is the value stored in userName variable.

So let userName= 5 then the output of this corrected line is as following:

Num is: 5

8 0
2 years ago
a 250 pound person would use a type 1 ladder even if they were carrying a load with them true or faults​
Marysya12 [62]

Answer:True

Explanation:

6 0
2 years ago
Read 2 more answers
The force exerted on a bridge pier in a river is to be tested in a 1:10 scale model using water as the working fluid. In the pro
Len [333]

Answer:

Force on the prototype is 5000 N

Solution:

As per the question:

Depth of water, x = 2.0 m

Flow velocity, v' = 1.5 m/s

Width of the river, w = 20 m

Force on the bridge pier model, F' = 5 N

Pressure, Ratio = Ratio of scale length

Scale = 1:10

Now,

\frac{P'}{P} = \frac{x}{w} = \frac{2.0}{20}

where

P' = pressure on model

P = pressure on prototype

\frac{\frac{F'}{A'}}{\frac{F}{A}} = \frac{1}{10}

where

F' = Force on model

F = Force on prototype

A' = Area of model

A = Area of prototype

Now:

\frac{F'}{F}.\frac{A}{A'} = \frac{1}{10}

\frac{5}{F}.\frac{1}{\frac{1}{10}}.\frac{1}{\frac{1}{10}} = \frac{1}{10}

F = 5000 N

3 0
2 years ago
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