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Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot

Anastasy [175]

Option B : $\frac{1}{\sqrt[3]{x^{5} } }$ is the expression equivalent to $x^{-\frac{5}{3}$

Explanation:

The given expression is $x^{-\frac{5}{3}$

Rewriting the expression $x^{-\frac{5}{3}$ using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

$\frac{1}{x^{\frac{5}{3} } }$

Simplifying, we get,

$\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}$

Applying the rule, $a^{\frac{1}{n}}=\sqrt[n]{a}$

Thus, we have,

$\frac{1}{\sqrt[3]{x^{5} } }$

Now, we shall determine from the options that which expression is equivalent to $x^{-\frac{5}{3}$

Option A: $\frac{1}{\sqrt[5]{x^{3} } }$

The expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option A is not the correct answer.

Option B: $\frac{1}{\sqrt[3]{x^{5} } }$

The expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to $x^{-\frac{5}{3}$

Hence, Option B is the correct answer.

Option C: $-\sqrt[3]{x^5}$

The expression $-\sqrt[3]{x^5}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[3]{x^5}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option C is not the correct answer.

Option D: $-\sqrt[5]{x^3}$

The expression $-\sqrt[5]{x^3}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[5]{x^3}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option D is not the correct answer.

4 0

2 years ago

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There are 53 students on the Jackson Middle School basketball teams. The number of 8th graders is 15 fewer than three times the

pshichka [43]

Answer:

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

Step-by-step explanation:

Let

x ----> the number of 7th students on the Jackson Middle School basketball teams

y ----> the number of 8th students on the Jackson Middle School basketball teams

we know that

There are 53 students on the Jackson Middle School basketball teams

so

$x+y=53$ -----> equation A

The number of 8th graders is 15 fewer than three times the number of 7th graders

so

$y=3x-15$ ----> equation B

substitute equation B in equation A

$x+(3x-15)=53$

solve for x

$x+3x=53+15\\4x=68\\x=17$

Find the value of y

$y=3(17)-15=36$

therefore

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

6 0

2 years ago

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Solve for x. −12 = − 3/4 x A) 6 B) 8 C) 12 D) 16

shepuryov [24]

Answer:

D) 16

Step-by-step explanation:

5 0

2 years ago

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On an algebra test, the highest grade was 42 points higher than the lowest grade. The sum of the two grades was 138. Find the lo