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2 years ago

Find the volume of a regular tetrahedron whose altitude measures 10cm.

1 answer:

5 0

H = 10 cm, a - edge;
V = 1/3 a²√3 / 4 * h
h² = ( 2/3 * a√3 / 2 )² + a²
100 = a²/3 + a²
100 = 4 a² / 3
a² = 75
a = √75
a = 5 √3 cm
V = 1/2 * 75√3 / 4 * 10 = 250√3 / 4 = 62.5√3 cm³ ≈ 108.25 cm³

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Name the value of each 2 in the number 222,222

nirvana33 [79]

Two hundred thousand 200,000
twenty thousand    20,000
two thousand        2,000
two hundred 200
twenty 20
two    2
      222,222
Hope I helped! : )

3 0

2 years ago

In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a

UNO [17]

Answer:

T = - 7.5 Cos π/12( t - 4 ) + 10.5

Step-by-step explanation:

Given that the

Maximum temp. = 18 degree Celsius

Minimum temp. = 3 degree Celsius

The half way between 10 am and 10 pm is 4 am

The sine and cosine functions can be used to model fluctuations in temperature data through out the year. An equation that can be used to model these data is of the form:

T = A cos B(t - C) + D, where A,B,C,D, are constants, T is the temperature in °C and t is the hour (1–24)

A = amplitude = (Tmax - Tmin)/2

A = (3 - 18)/2 = - 15/2 = -7.5 ( note : after midnight)

B = 2π/24 = π/12

C = units translated to the right

C = 4

D = ymin + amplitude = units translated up

D = 7.5 + 3 = 10.5

The formula of the trigonometric function that models the temperature T in Johannesburg t hours after midnight we be

T = - 7.5 Cos π/12( t - 4 ) + 10.5

3 0

2 years ago

Question show in picture!

Wewaii [24]

Answer: H is the correct answer

Step-by-step explanation:

First, Kendra deposited $78 into her savings. Then, she added $50 more which is 128. She withdraw $27 and was left with $101

5 0

2 years ago

In a golf tournament, Sam played 4 rounds and was within 2 strokes of par for all 4 rounds of the tournament. If par is 72 on th

In-s [12.5K]

Given:

$|x-4(72)|=2$

To find:

The highest and lowest scores Sam could have made in the tournament.

Solution:

We have,

$|x-4(72)|=2$

$|x-288|=2$

It can be written as

$x-288=\pm 2$

Add 288 on both sides.

$x=288\pm 2$

$x=288-2$ and $x=288+2$

$x=286$ and $x=290$

Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.

8 0

2 years ago

A weatherman stated that the average temperature during July in Chattanooga is 80 degrees or less. A sample of 32 Julys is taken

baherus [9]

Answer:

The correct set of hypotheses is

$H_{0}$ : d=80 degrees

$H_{0}$ : d>80 degrees

Step-by-step explanation:

The weatherman claims that the average temperature during July in Chattanooga is 80 degrees or less. To test this claim, following hypotheses need to be taken:

Let d be the the average temperature during July in Chattanooga, then

$H_{0}$ : d=80 degrees

$H_{0}$ : d>80 degrees

7 0

2 years ago