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gogolik [260]
2 years ago
7

Si un barco navega en el mismo sentido de la corriente de un rio, consume menos combustible que cuando va en sentido contrario d

e la corriente ¿Como explicarias este comportamiento en el consumo de combustible?
Chemistry
1 answer:
aleksley [76]2 years ago
7 0

Answer:

La respuesta a tu pregunta esta abajo.

Explanation:

Cuando un barco navega en un río en el sentido de la corriente, la velocidad que lleva más el impulso que le proporciona la corriente, hace que avance más rápido llegando más pronto a su destino sin tanto esfuerzo del motor. Por lo que gastaría una menor cantidad de combustible.

Cuando el barco se desplaza en sentido contrario a la corriente del motor, la corriente del río hace que su desplazamiento neto sea menor ya que el barco avanza y el río lo regresa un tramo y el esfuerzo del motor el mayor.

En estas condiciones aunque el barco tenga que recorrer la misma distancia que en el caso anterior, en realidad debería sumarse la distancia que lo regresa la corriente y por lo tanto el combustible gastado sera mayor.

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Which of the following is correctly balanced redox half reaction? Group of answer choices A. 14H+ + 9e- + Cr2O72- ⟶ Cr3+ + 7H2O
oee [108]

Answer:

The correct option is: B. 14 H⁺ + 6 e⁻ + Cr₂O₇²⁻ ⟶ 2 Cr³⁺ + 7 H₂O

Explanation:

Redox reactions is an reaction in which the oxidation and reduction reactions occur simultaneously due to the simultaneous movement of electrons from one chemical species to another.

The reduction of a chemical species is represented in a reduction half- reaction and the oxidation of a chemical species is represented in a oxidation half- reaction.

<u>To balance the reduction half-reaction for the reduction of Cr₂O₇²⁻ to Cr³⁺</u>:

Cr₂O₇²⁻ ⟶ Cr³⁺

First the <u>number of Cr atoms</u> on the reactant and product side is balanced

Cr₂O₇²⁻ ⟶ 2 Cr³⁺

Now, Cr is preset in +6 oxidation state in Cr₂O₇²⁻ and +3 oxidation state in Cr³⁺. So each Cr gains 3 electrons to get reduced.

Therefore, <u>6 electrons are gained</u> by 2 Cr atoms of Cr₂O₇²⁻ to get reduced.

Cr₂O₇²⁻ + 6 e⁻ ⟶ 2 Cr³⁺

Now the total charge on the reactant side is (-8) and the total charge on the product side is (+6).

From the given options it is evident that the reaction must be balanced in acidic conditions.

Therefore, to <u>balance the total charge</u> on the reactant and product side,<u> 14 H⁺ is added on the reactant side.</u>

Cr₂O₇²⁻ + 6 e⁻ + 14 H⁺ ⟶ 2 Cr³⁺

Now to <u>balance the number of hydrogen and oxygen atoms, 7 H₂O is added on the product side.</u>

Cr₂O₇²⁻ + 6 e⁻ + 14 H⁺ ⟶ 2 Cr³⁺ + 7 H₂O

<u>Therefore, the correct balanced reduction half-reaction is:</u>

Cr₂O₇²⁻ + 6 e⁻ + 14 H⁺ ⟶ 2 Cr³⁺ + 7 H₂O

3 0
2 years ago
Which of the following mixtures, with each component present at a concentration of 0.1 M, has a pH closest to 7? O A. HCIO(aq) a
eduard

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15                                    

for CH3 COOH, pKa = 4.74    

Explanation:

The concentration of the solution given is 0.1 M has a pH closest to 7

The mixtures are weak acids and their salts except

HNO_3 and NaNO_3                                         pH = pH is near to '1'

for buffers( acidic)                                               pH = pKa + log [salt] / [acid]

therefore [salt] = [acid] = 0.1                               pH = pKa + log 0.1 / 0.1 = pKa

                                                     pH = pKa

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15                                     therefore HClO and NaclO

                                                                         mixture hs a pH closest to '7'

for CH3 COOH, pKa = 4.74                

5 0
2 years ago
Read 2 more answers
What is the mass % of acetonitrile in a 2.17 M solution of acetonitrile (MM = 41.05 g/mol) in water? The density of the solution
jonny [76]

why how what what what

5 0
2 years ago
The feed to an ammonia synthesis reactor contains 25 mole% nitrogen and the balance hydrogen. The fow rate of the stream is 3000
Kisachek [45]

Answer:

The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.

Explanation:

Mole percentage of nitrogen gas  = 25 mole%

Mole percentage of hydrogen  gas  = 75 mole%

Average molecular weight of the mixture:

(0.25\times 28 g/mol)+(0.75\times 2 g/mol)=8.5 g/mol

Rate of flow of the stream = 3000 kg/h

Mass of stream in 1 hour = 3000 kg = 3,000,000 g

Moles of stream :

\frac{3000 g}{8.5 g/mol}=352,941.17 mol

Moles of nitrogen gas in 352,941.17 moles of stream be x

25\%=\frac{\text{Moles of nitrogen gas}}{\text{Moles of stream}}\times 100

25=\frac{x}{352,941.17mol}\times 100

x = 88,235.294 mol

Mass of 8,823,529.4 mole of nitrogen gas:

88235.294 mol\times 28 g/mol=2.470588.2 g=2,470.588 kg

The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.

8 0
2 years ago
Phosphoric acid, which is commonly used as rust inhibitor, food additive and etching agent for dental and orthopedic use, can be
Pachacha [2.7K]

Answer:

P4(l) + 5O2(g) + 6H2O(l) → 4H3PO4(aq)

Explanation:

Step 1

P4(l)+ 5O2(g) → 2P2O5()

Step 2

2P2O5(g)+ 6H2O(l) → 4H3PO4(aq)

Overall balanced equation;

P4(l) + 5O2(g) + 6H2O(l) → 4H3PO4(aq)

Notice carefully that the correct coefficients were used to balance the equations and obtain the accurate overall reaction equation. All the steps involved were shown above. Reactants that occur on both sides cancel out and do not appear in the final equation.

8 0
2 years ago
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