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yan [13]
2 years ago
15

Is utensils a substance homogeneous mixture or heterogeneous mixture

Chemistry
1 answer:
Phoenix [80]2 years ago
7 0

A pure substance or a homogeneous mixture consists of a single phase. A heterogeneous mixture consists of two or more phases. When oil and water are combined, they do not mix evenly, but instead form two separate layers.

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A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
1 year ago
What is charge on the cation SnCl4
Rasek [7]
Its total charge is zero but for the elements:
Sn===> Sn4+ positive
Cl===> Cl- negative
7 0
2 years ago
Read 2 more answers
How many structures are possible for a trigonal bipyramidal molecule with a formula of ax3y2?
ryzh [129]
Check the attached file for the answer.

4 0
2 years ago
In this activity, several changes will be made to samples of matter. Your challenge will be to decide if the change is physical
Rus_ich [418]

Answer:

Step 1: Burning Candle - Mass- 2.19 The wick of the candle changed colors, from white to black. The shape and height of the candle changed.

Step 2: Cooling Candle - Mass- 2.18, The shape of the has a flat surface.

Step 3: Tearing paper - The paper is somewhat easy to tear, and its edges change shape. It does take a bit to tear it into pieces though.

Step 4: Wet paper - It absorbed the water easily. It became very fragile.

Step 5: Burning pieces of paper - The paper burned fast, it changed color and folded inward and downward.

Step 6: Salt and water in test tube - The water changed color and even bubbled. Small particles of salt dissolve.

Step 7: Baking soda and vinegar - The substance bubbled and changed to a white yet somewhat transparent color.

In chemical changes, composition is the factor that changes, and it's sometimes harder to identify a chemical change as it can't always be seen. Whereas physical changes are more easily identifiable because they include smell, color, anything to do with appearance.

In the candle tests, it was a physical change because its physical appearance changed, such as its height, mass, and color of the wick. The tearing paper test was a physical change too because its physical appearance changed. It’s shape being the main change. I think the burning the paper was both physical and chemical because its physical appearance, the color and shape, changed. But the properties of it changed too, because it went from being paper to being ashes. The salt & water and the baking soda & vinegar were both chemical changes because some properties changed and they formed new substances. Both things caused a gas like substance to form which caused the bubbling formation of both.

Explanation:

..........

8 0
1 year ago
If the same amount of heat is supplied to samples of 10.0 g each of aluminum, iron, and copper all at 15.0 °c, which sample woul
lozanna [386]

The specific heat of aluminum, iron and copper is 0.897 J/g °C, 0.452 J/g °C and 0.385 J/g °C respectively.

The formula that relates specific heat capacity and change in temperature is as follows:

E=m×c×ΔT

Here, E is heat, m is mass, c is specific heat and ΔT is change in temperature.

On rearranging,

c=\frac{E}{m\times \Delta T}

Thus, change in temperature is inversely proportional to change in temperature. Change in temperature will be more for the element with low value of specific heat which is Cu in this case.

Since, the initial temperature is same for all the samples thus, Cu will reach the highest  temperature.

6 0
2 years ago
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