Answer:
Ok:
Explanation:
So, you can use the Henderson-Hasselbalch equation for this:
pH = pKa + log() where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.
We can solve that
1 = log() and so 10 =
or 10HA = A-. For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.
Acetic acid (CH3COOH) is a weak acid while methylamine (CH3NH2) is a weak base. During an acid base reaction, an acid tends to lose a proton while a base tends to accept a proton. The reaction at equilibrium is as follows:
↔
Hence the species in equilibrium are:
Acetate anion: CH3COO-
Methyl ammonium cation: CH3NH3+
Explanations:- As per the significant figures rule, In multiplication and division, we go with least number of sig figs.
4.03 has three sig figs where as 0.0000035 has two sig figs only, The zeros in this number are not sig figs as they are just holding the place values. As the least number of sig figs here is two, the answer needs to be reported with two sig figs only.