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pychu [463]
2 years ago
15

A mass of 5.4 grams of aluminum (al) reacts with an excess of copper (ii) chloride (cucl2) in solution, as shown below. 3cucl2 2

al → 2alcl3 3cu what mass of solid copper (cu) is produced
Chemistry
1 answer:
horrorfan [7]2 years ago
8 0

Answer:

Mass of copper produced is 19.07g

Explanation:

Let's bring out the chemical equation;

3CuCl2 + 2Al → 2AlCl3 + 3Cu

3           :   2       :   2       : 3

Upon confirming that the reaction is indeed balanced, we can proceed.

The questions asks to calculate mass of Cu formed when a mass of 5.4g of Al is being used.

From the equation, what is the relationship between Al and Cu?

2 mol of Al would react to form 3 mol of Cu

Expressing this in terms of mass, we have;

mass = no. of moles * molar mass

Mass of Aluminium = 2 * 26.98 = 53.98 g

Mass of Copper = 3 * 63.546 = 190.638g

This means;

53.98 g of Al would react to form 190.638g of Cu

So how much Cu would form from 5.4 g of Al?

This leads us to;

53.98 = 190.638

5.4 = x

Upon cross multiplication, we are left with;

x = (190.638 * 5.4) / 53.98

x = 19.07 g

Mass of copper produced is 19.07g

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2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio?
mash [69]
You did not include the options but I can tell you the product ratio.

The product ratio is the mole ratio of the products of the reaction.

From the balanced chemical equation you have all the mole ratios:

The given equation is: 2 C6H5COOH + 15O2 --> 14 CO2 + 6H2O

The mole ratios are: 2 C6H5COOH: 15 O2: 14 CO2 : 6 H2O

The products are CO2 and H2O

Their mole ratio = 14 CO2 : 6 H2O

That can be expressed as:

14 mol CO2        7 mol CO2
----------------- =  -----------------
  6 mol H2O        3 mol H2O

It is also the same that:

6 mol H2O : 14 mol CO2

  6 mol H2O           3 mol H2O
------------------ =  -------------------
14 mol CO2           7 mol CO2

So, compare your options to the ratios show above and pick the proper ratio.
7 0
2 years ago
How many iodide ions are present in 65.5ml of .210 m AlI3 solution
blondinia [14]

Answer:

2.48\times 10^{22} ions are present in solution.

Explanation:

Molarity of the solution = 0.210 M

Volume of the solution = 65.5 ml = 0.0655 L

Moles of aluminum iodide= n

Molarity=\frac{\text{Moles of compound}}{\text{Volume of the solution(L)}}

0.210M=\frac{n}{0.0655 L}

n = 0.013755 moles of aluminum iodide

1 mole of aluminum iodide contains 3 moles of iodide ions:

Then 0.013755 moles of aluminum iodide will contain:

3\times 0.013755 moles=0.041265 mol of iodide ions

Number of iodide ions in 0.041265 moles:

0.041265 mol\times 6.022\times 10^{23}=2.48\times 10^{22} ions

2.48\times 10^{22} ions are present in solution.

7 0
2 years ago
List the salts in order from weakest to strongest lattice energy (most positive to most negative). magnesium chloride, barium ch
almond37 [142]

Answer: Option (6) is the correct answer.

Explanation:

Lattice energy is described as the energy released when formation of 1 mole of an ionic compound occurs due to the combination of its constituent ions.

Also, lattice energy is inversely proportional to the distance between the cation and anion. And, when we move down a group then there occurs an increase in the atomic radii of the atoms.

This means that smaller is the ionic distance between the cation and anion, more will be the lattice energy between the atoms.

Therefore, order from weakest to strongest lattice energy (most positive to most negative) for the given compounds is as follows.

 barium chloride < strontium chloride < calcium chloride < magnesium chloride

6 0
2 years ago
The first five ionization energies of an element are as follows (in kJ/mol): 577.9, 1820, 2750, 11600, 14800. Which of the follo
Ne4ueva [31]

Answer:option d==> Si.

Explanation:

The energy required to remove electron from a gaseous atom or ion is what is called an ionization energy. As we remove electrons continually in a gaseous atom or ion, the ionization energy increases which are know as the first ionization energy, the second ionization energy, third ionization energy and so on.

Looking at the electronic configuration of Silicon, Si; Ne 3s2 3p2. We can can see that the first four ionization energies are from the removal of the 3p2 and 3s2 electrons and the fifth ionization energy, which is the highest ionization energy of 14800 kJ/mol is the the electron removed from the core shell.

4 0
2 years ago
Interpret the following Arterial Blood Gases 1. pH 7.33 PaCO2 60 HCO3 34 A. Normal ABG values B. Respiratory acidosis without co
kicyunya [14]

Answer: 1) C; 2)D; 3)B; 4)B; 5) A

Explanation:Interpreting the following Arterial Blood gases, we have

1. pH 7.33 PaCO2 60 HCO3  34----Respiratory acidosis with partial compensation----C

2. pH 7.48 PaCO2 42 HCO3 30------. Metabolic alkalosis without compensation----D

3. pH 7.38 PaCO2 38 HCO3 24 ----- Normal---B

4. pH 7.21 PaCO2 60 HCO3 24------ Respiratory acidosis without compensation-----B

5. pH 7.48 PaCO2 28 HCO3 20 ----Respiratory alkalosis with partial compensation

The Arterial blood gas interpretation  from analysis shows  the pH and the partial pressures of oxygen and carbon dioxide in the arterial blood of an individual which can detect how well the lungs are functioning thereby making a physician make a diagnosis, estimate  the severity of a condition and profer treatment.

4 0
2 years ago
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